Thread For Your Useless Discoveries

[wwei23]

One of the P2 agars in jslife becomes P5 if S4 is added to the survival conditions.

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x = 40, y = 40, rule = B3/S234
5bo4bo4bo4bo4bo4bo$3bobo2bobo2bobo2bobo2bobo2bobo$2bo4bo4bo4bo4bo4bo4b
o$3b4ob4ob4ob4ob4ob4obobo$2obo2bobo2bobo2bobo2bobo2bobo2bobob3o$3bob2o
bob2obob2obob2obob2obob2obo4bo$bob3o2b3o2b3o2b3o2b3o2b3o2b5o$2bo31bo$
3b4ob4ob4ob4ob4ob4ob2o$2obo2bobo2bobo2bobo2bobo2bobo2bobob3o$3bob2obob
2obob2obob2obob2obob2obo4bo$bob3o2b3o2b3o2b3o2b3o2b3o2b5o$2bo31bo$3b4o
b4ob4ob4ob4ob4ob2o$2obo2bobo2bobo2bobo2bobo2bobo2bobob3o$3bob2obob2obo
b2obob2obob2obob2obo4bo$bob3o2b3o2b3o2b3o2b3o2b3o2b5o$2bo31bo$3b4ob4ob
4ob4ob4ob4ob2o$2obo2bobo2bobo2bobo2bobo2bobo2bobob3o$3bob2obob2obob2ob
ob2obob2obob2obo4bo$bob3o2b3o2b3o2b3o2b3o2b3o2b5o$2bo31bo$3b4ob4ob4ob
4ob4ob4ob2o$2obo2bobo2bobo2bobo2bobo2bobo2bobob3o$3bob2obob2obob2obob
2obob2obob2obo4bo$bob3o2b3o2b3o2b3o2b3o2b3o2b5o$2bo31bo$3b4ob4ob4ob4ob
4ob4ob2o$2obo2bobo2bobo2bobo2bobo2bobo2bobob3o$3bob2obob2obob2obob2obo
b2obob2obo2bobo$bob3o2b3o2b3o2b3o2b3o2b3o2bobo2bo$2bo31b3ob2o$3b4ob4ob
4ob4ob4ob4o5bo$6b3o2b3o2b3o2b3o2b3o3bo2bobo$3b2obo2bobo2bobo2bobo2bobo
2bob2obobo$4bobo2bobo2bobo2bobo2bobo2b2obo2bo$4bobo2bobo2bobo2bobo2bob
o2bo3b2o$5bo4bo4bo4bo4bo4b3o$32bo!

EDIT: The P64 thunderbird hassler "can" support the glider push reaction, if it weren't for the fact that the glider would have interacted with the spark two generations earlier, and that there seems to be no domino sparker that can support it without being destroyed by the glider.

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x = 22, y = 29, rule = LifeHistory
15.3A$15.3A$15.3A$12.3A$12.3A$12.3A3$12.2A$10.A6.A$10.A7.A$10.A$5.2A
4.A$4.A5.A.A4.A.3A$2.A2.2A4.A$A.A2.D4.A$.2A3.D3.A7.A$7.D2.A6.A$8.D3.
2A$9.D2.2D$10.D$11.D3A$12.3A$.2A9.3A$.2A3.A7.D3A$5.A.A7.3A$6.A.A6.3A$
8.A$8.2A!

[LaundryPizza03]

One of the P2 agars in jslife becomes P5 if S4 is added to the survival conditions.

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B3/S234

There is a thread for that rule here.

[MathAndCode]

I doubt that it would be possible to get a conduit out of this (although that's what I thought last time).

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x = 19, y = 13, rule = TripleB3S23
17.2G$17.2G5$12.2G$11.2G$12.G2$.G$G.G$AGD!
#C [[ PASTEMODE COPY ]]
#C [[ RLE empty 4.$4.! ]]
#C [[ PASTET 30 ]]
#C [[ PASTE empty -1 10 ]]

[wwei23]

Best honey farm predecessor ever?

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x = 21, y = 21, rule = B3/S23
b2o$o2bo$obo$bo$5b3o$4bo2bo$4bo2bo$4b3o6$14b3o$13bo2bo$13bo2bo$13b3o$
19bo$18bobo$17bo2bo$18b2o!

[MathAndCode]

Best honey farm predecessor ever?

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x = 37, y = 37, rule = B3/S23
19b2o$19b2o$11b3o3$16bo3bo$15bo5bo$16bo3bo$11b2o4b3o$11b2o2$27b2o5bo$27b2o5bo$34bo2$6bo23bo$2o3bobo21bobo$2o6bo19bo$8bo19bo$8bo19bo6b2o$5bobo21bobo3b2o$6bo23bo2$2bo$2bo5b2o$2bo5b2o2$24b2o$17b3o4b2o$16bo3bo$15bo5bo$16bo3bo3$23b3o$16b2o$16b2o!

[ENORMOUS_NAME]

bookend dies and then gets r e b o r n

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x = 15, y = 894, rule = B3/S23
5b2ob2o$5b2ob2o2$5b2ob2o$6bobo$4bobobobo$4b2o3b2o13$4bo5bo$3b3o3b3o$2b
o2bo3bo2bo$b3o7b3o$2bobo5bobo$4b2o3b2o$o4bo3bo4bo$5bo3bo$2o3bo3bo3b2o$
2bo2bo3bo2bo$4bo5bo206$4bo5bo$3b3o3b3o$2bo2bo3bo2bo$b3o7b3o$2bobo5bobo
$4b2o3b2o$o4bo3bo4bo$5bo3bo$2o3bo3bo3b2o$2bo2bo3bo2bo$4bo5bo206$4bo5bo
$3b3o3b3o$2bo2bo3bo2bo$b3o7b3o$2bobo5bobo$4b2o3b2o$o4bo3bo4bo$5bo3bo$
2o3bo3bo3b2o$2bo2bo3bo2bo$4bo5bo206$4bo5bo$3b3o3b3o$2bo2bo3bo2bo$b3o7b
3o$2bobo5bobo$4b2o3b2o$o4bo3bo4bo$5bo3bo$2o3bo3bo3b2o$2bo2bo3bo2bo$4bo
5bo206$4bo5bo$3b3o3b3o$2bo2bo3bo2bo$b3o7b3o$2bobo5bobo$4b2o3b2o$o4bo3b
o4bo$5bo3bo$2o3bo3bo3b2o$2bo2bo3bo2bo$4bo5bo!

[Schiaparelliorbust]

Super useless way to get an LWSS:

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x = 43, y = 15, rule = B3/S23
x = 34, y = 14, rule = B3/S23
25b2o$25b2o$32bo$6bo24bobo$5bobo23bobo$5bobo24bo$6bo2$b2o7b2o$o2bo5bo
2bo11b2o$b2o7b2o11bo2bo$23bobo$7b2o14b2o$7b2o!

Is there any way to synthesize that loaf-like pattern?

[MathAndCode]

Is there any way to synthesize that loaf-like pattern?

It can be made by hitting a boat or a ship with a glider.

A ship is a one-glider seed for Block and glider.

A boat is also a one-glider seed for block-and-glider; you can just remove one cell from the ship, but you have to move the glider over by one lane.
And something that I just noticed this morning is that that boat+glider --> block-and-glider can be triggered by gliders coming from two different directions:

[Entity Valkyrie 2]

Useless mechanism:

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x = 47, y = 89, rule = B3/S23
9bo2bo$7b3o2b3o$6bo3b2o3bo$5bo2bobo2bobo9bo$5bob2o3b3o10b3o10bo$4b2o2b
o19bo7b3o$3bo2bo2b6o12b2o6bo$3bobo3bo3bobo19b2o$2b2ob2o2b3o3bo$bo6bo3b
3o$b5ob2obobo$5b2o2bobo$b2o15b2o$b2o15b2o2$40b2o$40bobo$41bo$bo$obo$ob
o$bo10$43b2o$43bobo$45bo$45b2o20$45b2o$45bo$43bobo$43b2o7$7bo$5b2o$6b
2o$bo$obo$obo$bo$41bo$40bobo$40b2o2$b2o15b2o$b2o15b2o$5b2o2bobo$b5ob2o
bobo$bo6bo3b3o$2b2ob2o2b3o3bo$3bobo3bo3bobo19b2o$3bo2bo2b6o12b2o6bo$4b
2o2bo19bo7b3o$5bob2o3b3o10b3o10bo$5bo2bobo2bobo9bo$6bo3b2o3bo$7b3o2b3o
$9bo2bo!

[MathAndCode]

Put that block back where you found it.

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x = 17, y = 36, rule = LifeHistory
7.D$7.2DB$6.2D2B$6.D4B$5.6B$5.5B$5.6B$A4.6B$3A2.7B$3.A.7B$2.A.7B$2.2A.6B$5.7B$5.7B$5.6B2.B$5.B3C2B.B2A$5.3BC4B2A$5.B3C2B.2B$5.6B$5.7B$5.7B$5.6B$6.6B$6.8B2A$4.A9B2A$3.A.A2.9B$3.2A5.7B$10.6B$11.5B$11.6B$11.6B$11.5B$11.2B3D$12.BDB$12.3D$13.B!

[otismo]

Super useless way to get an LWSS:

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x = 43, y = 15, rule = B3/S23
x = 34, y = 14, rule = B3/S23
25b2o$25b2o$32bo$6bo24bobo$5bobo23bobo$5bobo24bo$6bo2$b2o7b2o$o2bo5bo
2bo11b2o$b2o7b2o11bo2bo$23bobo$7b2o14b2o$7b2o!

Is there any way to synthesize that loaf-like pattern?

here is your LWSS and a Blinker :

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x = 24, y = 19, rule = B3/S23
9b2o$9b2o$16bo5bo$15bobo3bobo$15bobo3b2o$16bo$9b3o$5b2ob2obo$4b3ob2o2b
2o$2obo4b3o2bo$3bobo7bo$8bob3o$5b4o$7b2o3$5b2o$4bo2bo$5b2o!

[MathAndCode]

here is your LWSS and a Blinker :

I figured out a way to get a LWSS.

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x = 22, y = 10, rule = B3/S23
b2o$4o$2ob2o$2b2o4$10b2o$11b2o7b2o$11bo8b2o!

Now we just need an R-pentomino, a block, and an LWSS—oh, right.

[PC101]

This is frustratingly close but does not appear to be completabe.

A figure 8 will do. Now to remove the block somehow.

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x = 14, y = 19, rule = B3/S23
2b2o2$o3bo$o4bo$2bobobo$3bobobo$4bo4bo$5bo3bo2$6b2o4$12b2o$11b2o$3b2o
7bo$2bobo$2bo$b2o!

I found a way to remove that one block:

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x = 28, y = 26, rule = B3/S23
18bo$16b3o$15bo$15b2o$24b2o$24b2o2$2b2o$12b2o12b2o$o3bo7b2o12b2o$o4bo
10b2o$2bobobo9b2o$3bobobo16b2o$4bo4bo14b2o$5bo3bo6bo$14bobo7b2o$6b2o6b
3o7b2o4$12b2o$11b2o$3b2o7bo$2bobo$2bo$b2o!

[MathAndCode]

I found a way to remove that one block:

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x = 28, y = 26, rule = B3/S23
18bo$16b3o$15bo$15b2o$24b2o$24b2o2$2b2o$12b2o12b2o$o3bo7b2o12b2o$o4bo
10b2o$2bobobo9b2o$3bobobo16b2o$4bo4bo14b2o$5bo3bo6bo$14bobo7b2o$6b2o6b
3o7b2o4$12b2o$11b2o$3b2o7bo$2bobo$2bo$b2o!

There has already been work on this in the periodic conduits thread.

Regardless, I think this relatively compact form using Karel's p15 should prove that some versions of this reaction *can* be used in periodic conduit circuitry:

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x = 86, y = 54, rule = LifeHistory
26.B$25.BAB5.B$25.3A4.3B$24.ABABA3.BAB$24.ABABA2.BAB2A$23.2B3A2B.BAB
2A$23.3BA3B.3AB$22.9B.3B$22.9B.3B10.2A$23.3BA3B.3AB8.2B2AB8.2A$23.2B
3A2B.BAB2A7.4B9.A$24.ABABA2.BAB2A7.9B.BA.A$24.ABABA3.BAB9.8B.B2A$25.
3A4.3B8.11B$25.BAB4.3B8.12B$26.B5.5B.B.14B$7.4B7.A12.24B$8.4B6.3A8.B.
24B$9.4B8.A6.2C8B2D16B$10.4B6.2A6.2C7B2D18B$11.4B5.6B3.9BD18B$12.4B6.
5B2.3B4.50B$13.4B4.7B7.51B$14.4B2.8B7.51B$15.14B2.2B2.51B$16.22BD47B$
12.2A3.21BDBD4B.9B$13.A4.20B3D4B2.7B5.D.D.D.D.D.D.D.D.D.D.D.D.D.D$13.
A.AB.22BD4B2.7B10.A$14.2A28B4.6B5.D3.BAB5.B$15.17B.4B10.7B9.3B4.3A$
17.19B12.6B5.D2.2BA2B3.3B$8.A10.16B13.7B7.BABAB2.A3BA$8.3A8.15B14.6B
5.D.7B.B3AB$11.A7.14B15.5B8.2B3A2B.4B$10.2A3.B3.13B15.6B6.D9B.3B$10.
8B.12B16.4B9.9B.3B$12.18B17.2B2AB7.D.2B3A2B.4B$12.17B20.2A10.7B.B3AB$
11.17B31.D2.BABAB2.A3BA$9.18B35.2BA2B3.3B$7.19B33.D3.3B4.3A$7.2BC15B
38.BAB4.3B$6.3BCBC4B.9B33.D4.A5.5B.B$7.2B3C4B2.7B44.9B$6.5BC4B4.5B34.
D7.B.10B$5.10B3.5B43.2C8B2CB$4.4B10.2A39.D6.2C7B2C2B$4.3B12.A47.9BC2B
$2.4B10.3A40.D7.3B4.12B$2.2A12.A56.13B$3.A55.D13.13B$3A71.12B$A58.D
14.12B!

Also, here's another partial LWSS-making conduit.

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x = 19, y = 15, rule = B3/S23
4bo$3bobo$3bobo$b3ob2o$o$b3ob2o$3bob2o9b2o$15bo2bo$14bo2bo$14b3o4$3b2o$3b2o!

This one doesn't look as promising, though.

[Schiaparelliorbust]

here is your LWSS and a Blinker :

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x = 24, y = 19, rule = B3/S23
9b2o$9b2o$16bo5bo$15bobo3bobo$15bobo3b2o$16bo$9b3o$5b2ob2obo$4b3ob2o2b
2o$2obo4b3o2bo$3bobo7bo$8bob3o$5b4o$7b2o3$5b2o$4bo2bo$5b2o!

How are they the same reaction? I don't see the resemblance. Sorry if it's obvious.

[MathAndCode]

How are they the same reaction? I don't see the resemblance. Sorry if it's obvious.

Look at generation 37 of your pattern. Otismo's pattern appears to have removed objects that are not necessary for the LWSS's creation. However, doing that causes the LWSS to crash into a century instead of escaping, so otismo had to add other objects in order to suppress the junk that would have been suppressed by the objects that otismo removed.

[Kazyan]

Result from a deep (multi-day) CatForce search:

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#C [[ STOP 80 ]]
x = 15, y = 22, rule = LifeHistory
9.2C$8.C2.C$9.2C4$9.2C$8.C2.C$9.2C$2C$2C4$5.2C$5.2C3.3A$9.A3.A$8.A5.A
$8.A2.D2.A$8.A5.A$9.A3.A$10.3A!

The blinker from the Beethoven does not appear to be cleanable, though, because there's a cell that interferes with the spot where you'd normally place a fishhook. Interesting, though.

[wwei23]

The blinker from the Beethoven does not appear to be cleanable, though, because there's a cell that interferes with the spot where you'd normally place a fishhook.

Use a T-nosed P4 or something like that with a blinker-deleting spark. I think 230P8 would fit there.

[MathAndCode]

Use a T-nosed P4 or something like that with a blinker-deleting spark. I think 230P8 would fit there.

Yes, but people typically prefer stable catalysts. Sparkers can be useful, but conduits that work at any generation instead of only every 30th step or so are typically preferred (although in this particular case, the exact timing of deleting the blinker doesn't matter).

[wwei23]

Yes, but people typically prefer stable catalysts. Sparkers can be useful, but conduits that work at any generation instead of only every 30th step or so are typically preferred (although in this particular case, the exact timing of deleting the blinker doesn't matter).

A pentadecathalon will probably do, if it fits. 15 is relatively prime with 2, so it has to delete the blinker eventually. I think it would delete the blinker before the conduit could be used again either way.

[MathAndCode]

A pentadecathalon will probably do, if it fits. 15 is relatively prime with 2, so it has to delete the blinker eventually. I think it would delete the blinker before the conduit could be used again either way.

Unfortunately, the blinker interacts with the pentadecathlon one generation too early.

Code: Select all

x = 18, y = 5, rule = B3/S23
2b2o6b2o$o4bo2bo4bo$o4bo2bo4bo$o4bo2bo4bob3o$2b2o6b2o!

[wwei23]

Unfortunately, the blinker interacts with the pentadecathlon one generation too early.

I was thinking of using the side spark, not the end spark.

[Kazyan]

The side spark of a pentadecathlon does not fit. By moving the non-transparent block down one cell, though, a fumarole (p5; coprime to p2) can be made to work:

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#C [[ STOP 80 ]]
x = 18, y = 23, rule = LifeHistory
2A$A2.3A6.2C$.2A8.C2.C$6.A5.2C$6.A$.2A$A2.3A$2A10.2C$11.C2.C$12.2C2$
3.2C$3.2C3$8.2C$8.2C3.3A$12.A3.A$11.A5.A$11.A2.D2.A$11.A5.A$12.A3.A$
13.3A!

I don't know if slparse knows how to make a fumarole, but it should be doable. Taming of the rest of the pattern may come tonight, and hopefully it can move out of Useless Discoveries.

[MathAndCode]

I was thinking of using the side spark, not the end spark.

Here's another useless discovery (that may not be new): An Octagon 2 can cleanly delete a blinker.

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x = 9, y = 15, rule = B3/S23
5b3o$4bo3bo$4bo3bo$4bo3bo$5b3o3$3b2o$2bo2bo$bo4bo$o6bo$o6bo$bo4bo$2bo2bo$3b2o!

It's useless because it only works if the blinker is created at that exact time.

[mniemiec]

Here's another useless discovery (that may not be new): An Octagon 2 can cleanly deleted a blinker. ... It's useless because it only works if the blinker is created at that exact time.

Not necessarily useless; it might be possible to use it as part of a P5n mechanism (e.g. like some kind of pre-pulsar shuttle or traffic jam) to remove one side of a forming traffic light. I know there are already some mechanisms that will do that, but it's possible that this might fill a niche somewhere.