iNoMed wrote: ↑June 6th, 2021, 9:22 am
Blocked p4-3 in 59G using that blueprint, the other oscillators shouldn't vary too much in terms of cost:
I managed to save three gliders by consolidating two steps.
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x = 181, y = 29, rule = B3/S23
171bobo$171b2o$172bo3$170bo$168bobo$4bo164b2o2bobo$5b2o166b2o$4b2o168b
o$48bo$46bobo$10bo36b2o$10bobo37bo$5bo4b2o38bobo$6b2o42b2o$5b2o$164b2o
$2b2o38b2o3b2o116bo$3bo39bo4bo116bob2o$3bob2o36bob3o6b2o106b2obobobo$
2obobobo32b2obobo7b2o107b2obo2bo$2obo2bo33b2obo11bo109bo$3bo8b2o29bo
121bobo$3bobo6bobo28bobo120b2o$4b2o6bo31b2o$178b2o$178bobo$178bo!
There are possibilities for the other oscillators, but they don't look nearly as realistic.
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x = 87, y = 12, rule = B3/S23
47bo33bobo$10bo33bo3bo32bo3bo$8bobo35bobo34bobo$6bobo35bobo34bobo$2b2o
3bo32b2o3bo31b2o3bo$3bo37bo36bo$3bob4obo30bob4obo29bob4obo$2obobo5bo
26b2obobo5bo25b2obobo5bo$2obo2bo31b2obo2bo30b2obo2bo$3bo37bo36bo$3bobo
35bobo34bobo$4b2o36b2o35b2o!
Here is another pair of steps that could potentially be consolidated:
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x = 81, y = 21, rule = B3/S23
7b2o2b2o48b2o2b2o$2b2o3bo3bobo3b2o37b2o3bo3bobo3b2o$3bo4bo3bo4bo39bo4b
o3bo4bo$3bob3o5b3obo39bob3o5b3obo$2obobo9bobob2o33b2obobo9bobob2o$2ob
o11bobob2o33b2obo13bob2o$3bo12bo40bo13bo$3bobo51bobo10b2o$4b2o52b2o2$
8b3o$10bo7b2o$9bo8bobo42b2o4bo$18bo43bobo3b2o$64bo3bobo$9b3o47bo$11bo
47b2o$10bo47bobo17b2o$69b2o7bobo$68b2o8bo$70bo!
One possible avenue is the following:
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x = 21, y = 11, rule = B3/S23
7b2o2b2o$2b2o3bo3bobo3b2o$3bo4bo3bo4bo$3bob3o5b3obo$2obobo9bobob2o$2o
bo11bobob2o$3bo12bo$3bobo9b2o$4b2o7bob2o$13bo$15b2o!
It looks promising because most of that can be done with only two gliders. Getting the left domino spark in will be tricky due to the clearance, but even a five-glider solution would result in a reduction. Here's a three-glider method that works with better clearance that I'm using to illustrate my thought concept:
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x = 49, y = 37, rule = B3/S23
obo$b2o$bo4$23b2o$23bobo3b2o$24bo4bo$25b3obo$27bobob2o$27bobob2o$28bo
14$27b3o$27bo$28bo3$10b2o$9bobo$11bo$b3o43b2o$3bo42b2o$2bo45bo!
Lastly, I think that it might be possible to save some gliders by applying a fast component to the first step. The best that I've found so far ties your version in cost, but I'll keep looking.
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x = 50, y = 49, rule = B3/S23
44bo$43bo$39bo3b3o$38bo$38b3o4$16bobo29bo$16b2o29bo$17bo29b3o$13bo$12b
o8bobo$12b3o6b2o$22bo15$16b3o$16bo$17bo4$b2o$obo$2bo9bo$12b2o31bo$11b
obo30b2o$44bobo2$7b2o$6bobo$8bo2$40b2o$39b2o$41bo!
Edit: The spark for the tub can be made more feasibly if one uses death from overpopulation instead of just from underpopulation.
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x = 12, y = 11, rule = B3/S23
8b2o$8b2o$6bobo$2b2o3bo$3bo$3bob4obo$2obobo5bo$2obo2bo$3bo$3bobo$4b2o!
Similar methods also work for the beehive and trans-boat.
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x = 115, y = 13, rule = B3/S23
9bo51bo49bo$8b2o50bo51bo$8b2o50b2o49b2o$6bob2o50b2o49b2o$6bobo49bobo
48bobo$2b2o3bo46b2o3bo45b2o3bo$3bo51bo50bo$3bob4obo44bob4obo43bob4obo$
2obobo5bo40b2obobo5bo39b2obobo5bo$2obo2bo45b2obo2bo44b2obo2bo$3bo51bo
50bo$3bobo49bobo48bobo$4b2o50b2o49b2o!
Another edit: I got a fishhook pseudo-on wing on bookend, which is interesting but not helpful in this situation.
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x = 121, y = 132, rule = B3/S23
42bobo$43b2o2bobo$43bo4b2o$48bo13$111bo$110bo$110b3o2$118bobo$118b2o$
88bobo20bo7bo$88b2o19b2o$89bo20b2o$85bo$84bo8bobo$84b3o6b2o$94bo20$47b
3o$49bo$48bo36$17bo$17b2o$16bobo27$88b3o$88bo$89bo4$b2o$obo$2bo2$113b
3o$113bo$114bo2$12bo$12b2o$11bobo!
Yet another edit: I got a tub with tail, which I think is more useful.
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x = 35, y = 31, rule = B3/S23
32bo$30b2o$31b2o3$9bo$8bo24bo$8b3o21bo$32b3o$6bo7bo$4b2o7bo$5b2o6b3o8$
9b2o$8b2o$10bo4$bo$b2o$obo$17b2o$16bobo$18bo!
I am tentatively considering myself back.