Four new almost-knightships CGOL

For discussion of specific patterns or specific families of patterns, both newly-discovered and well-known.
rokicki
Posts: 57
Joined: August 6th, 2009, 12:26 pm

Four new almost-knightships CGOL

Post by rokicki » February 14th, 2018, 12:13 am

Here are four more "almost-knightships" (1,2)c/6 that leave only two pixels wrong.
These are larger, but maybe someone can be clever enough to fix them . . . they
all share much of each other's prefixes.

Population 129:

Code: Select all

x = 23, y = 34, rule = B3/S23
3b3o$3bo2bo$3bob2ob2o$2b2o7b2o$bo5bo4bo$bo5bob2o3bo$o5bo3bobobo$o4b2o
3bobobo$bo3bo3bo$bobobobo2bobo$8bobob2o$6b2o5bo2b2o$13b5o$10bo2bo4bo$
10bobob2o$9b2ob2o3b2o$12bo2b2o$12b2obobo$13bo2b2obo$10b2obo5bo$11b4ob
3o$15bo2bobo$18bobo$19b2o$11b3o5bo2bo$22bo$16b2o4bo$11bo4bo3bo$11b3o2b
obo$14bo2b2obo$11bo2bo2b2o$19bo$12b3o$12b2o!
Population 149:

Code: Select all

x = 25, y = 39, rule = B3/S23
3b3o$3bo2bo$3bob2ob2o$2b2o7b2o$bo5bo4bo$bo5bob2o3bo$o5bo3bobobo$o4b2o
3bobobo$bo3bo3bo$bobobobo2bobo$8bobob2o$6b2o5bo2b2o$13b5o$10bo2bo4bo$
10bobob2o$9b2ob2o3b2o$12bo2b2o$12b2obobo$13bo2b2obo$10b2obo5bo$11b4ob
3o$15bo2bobo$18bobo$19b2o$11b3o5bo2bo$22bo$16b2o4bo$11bo4bo3bo$11b3o2b
obo$14bo2b3o$11bo2bo2bo2bo$19b2o2bo$12b3o3bob3obo$12b2o6bobobo$17bo$
17bo2bo$19b2o$21b3o$20bobo!
Population 182:

Code: Select all

x = 32, y = 47, rule = B3/S23
3b3o$3bo2bo$3bob2ob2o$2b2o7b2o$bo5bo4bo$bo5bob2o3bo$o5bo3bobobo$o4b2o
3bobobo$bo3bo3bo$bobobobo2bobo$8bobob2o$6b2o5bo2b2o$13b5o$10bo2bo4bo$
10bobob2o$9b2ob2o3b2o$12bo2b2o$12b2obobo$13bo2b2obo$10b2obo5bo$11b4ob
3o$15bo2bobo$18bobo$19b2o$11b3o5bo2bo$22bo$16b2o4bo$11bo4bo3b2o$11b3o
2bobo$14bo2b3o2bo$11bo2bo2b4o7bo$20bob2ob3obo$12b3o5bobo2b2o2bo$12b2o
8bobo2bo$22bo2bobo$22bo2b4o$23b2o2b2o$28bo$25bobo$25bo3b2o$25bo2$25bob
obo$24b2ob2ob2o$24b2ob2o2bo2$28bo!
Population 278:

Code: Select all

x = 38, y = 68, rule = B3/S23
3b3o$3bo2bo$3bob2ob2o$2b2o7b2o$bo5bo4bo$bo5bob2o3bo$o5bo3bobobo$o4b2o
3bobobo$bo3bo3bo$bobobobo2bobo$8bobob2o$6b2o5bo2b2o$13b5o$10bo2bo4bo$
10bobob2o$9b2ob2o3b2o$12bo2b2o$12b2obobo$13bo2b2obo$10b2obo5bo$11b4ob
3o$15bo2bobo$18bobo$19b2o$11b3o5bo2bo$22bo$16b2o4bo$11bo4bo3bo$11b3o2b
obo$14bo2b3o$11bo2bo2bo2bo$19b2o2bo$12b3o3bob3obo$12b2o6bobobo$17bo$
17bo3bo$23bob2o$20b4o$19bo3bo3bo$20b3ob4o$22bob4o$18b5ob5o$18bo2bo5bo$
18bob2o5b2o$18bo3bo4bob2o$22bo3bo$19b3o2$20b3o$20bo$21b3o$24bo$22b3o$
21bo3b2o$21b3obo$25bob2o$20bo5bo2bo$20bo2b2o2b2obo$20b3o5bo2bo$21bo9bo
3b3o$21b3o3bo2bo2b2ob2o$21b2ob2obo2bo2b2o$23b3obobo3b2o$29bobobo$25b7o
bo$25bobo6bo$31b4o2bo$33bo2b2o!

Sokwe
Moderator
Posts: 1899
Joined: July 9th, 2009, 2:44 pm

Re: Four new almost-knightships CGOL

Post by Sokwe » February 14th, 2018, 2:05 am

rokicki wrote:Here are four more "almost-knightships" (1,2)c/6 that leave only two pixels wrong.
These are larger, but maybe someone can be clever enough to fix them.
These are great! How did you find them?
rokicki wrote: they all share much of each other's prefixes.
I have actually seen the front of these partials before, but I never found anything as long as your last partial. I was originally interested in this partial, because it splits into two "strands" around rows 23 to 26. In your partials the strands quickly come back together to form a single strand again. It may be possible to find completions to each of these strands separately by searching in different directions (with WLS or something similar). I tried this several years ago, but did not get very far.
-Matthias Merzenich

rokicki
Posts: 57
Joined: August 6th, 2009, 12:26 pm

Re: Four new almost-knightships CGOL

Post by rokicki » February 14th, 2018, 1:22 pm

I found them using some ideas in other search programs, but using a SAT solver to do the actual searching.

Instead of row-by-row though, I kept a queue of partials, where here I define a partial as a pattern that, when advanced 6 generations and shifted by (-1, -2), had all differences (error bits) in a small (6x6, 7x7) rectangle on the lower right. For each partial, I put a square of "unknowns" that completely encompassed the error region (typically 9x9, 10x10, 11x11, and 12x12, but I've used as large as 15x15) and asked the SAT solver to find another (or rather, all) partials based on that. And then I just keep going. I run the small unknown squares first because they are fastest, but if I get stuck I'll run larger unknown regions.

At first I was excited because I was getting all of these partials really quickly and many of them seemed very promising. But after running things for about a week, I'm realizing that just because a partial is "close" doesn't mean it's necessarily actual progress towards a knightship.

Some of the partials get pretty big:

Code: Select all

x = 54, y = 73, rule = B3/S23
3b3o$3bo2bo$3bob2ob2o$2b2o7b2o$bo5bo4bo$bo5bob2o3bo$o5bo3bobobo$o4b2o
3bobobo$bo3bo3bo$bobobobo2bobo$8bobob2o$6b2o5bo2b2o$13b5o$10bo2bo4bo$
10bobob2o$9b2ob2o3b2o$12bo2b2o$12b2obobo$13bo2b2obo$10b2obo5bo$11b4ob
3o$15bo2bobo$18bobo$19b2o$11b3o5bo2bo$22bo$16b2o4bo$11bo4bo3bo$11b3o2b
obo$14bo2b3o$11bo2bo2bo2bo$19b2o2bo$12b3o3bob3obo$12b2o6bobobo$17bo$
17bo3bo$23bob2o$20b4o$19bo3bo3bo$20b3ob4o$22bob4o$18b5ob5o$18bo2bo5bo$
18bob2o5b2o$18bo3bo4bob2o$22bo3bo$19b3o2$20b3o$20bo$21b3o$24bo$22b3o$
21bo3b2o$21b3obo$25bob2o$20bo5bo2bo$20bo2b2o2b2obo$20b3o5bo2bo$21bo9bo
3b3o8b2o$21b3o3bo2bo2b2ob2o6b3ob2o$21b2ob2obo2bo2b2o8b2obobo$23b3obobo
3b2o7bo2bo2bo$29bobobo7b3o4bo$25b7obo8bo7bo$25bobo6bo7bobo5bo$31b2obo
2bo4bobo2bo3bo$35b2ob2o3bo4b3ob2o$36bob3o4bo7bo$38bo5bo3b3o$45bo3bo2b
2o$49b4o$49b2obo!
but then don't seem to extend easily any more.

I have thousands of partials with small error regions; it's not impossible that any
single one might be fixable. But the technique I'm using is probably running out
of steam and might need some refinements.

(I actually have many more partials than this; I canonicalize all partials that differ
only in the lower-right 8x8 square, and then ensure my "unknown" region overlaps
this fully.)

Based on this work over the past week, I'd have to say there's a good chance there's
an elementary (1,2)c/6 knightship out there, and it may well be found by someone
pretty soon using SAT solvers or other techniques. But at present based on the
results I have so far I probably would need to continue another two years before finding
an actual knightship.

And I believe the knightship found by this technique may well be extremely large;
perhaps a population of 1000 or more.

I'm a novice at these searches and have been helped tremendously by some suggestions
by a couple of members of this board. Maybe there are some other ideas out there that
will allow us progress.

User avatar
calcyman
Posts: 2418
Joined: June 1st, 2009, 4:32 pm

Re: Four new almost-knightships CGOL

Post by calcyman » February 15th, 2018, 9:59 am

I'd like to congratulate Tom for what is probably the first non-trivial progress on finding a knightship since Eugene Langvagen's almost-knightship and Tim Coe's partial.
Sokwe wrote:I have actually seen the front of these partials before, but I never found anything as long as your last partial. I was originally interested in this partial, because it splits into two "strands" around rows 23 to 26. In your partials the strands quickly come back together to form a single strand again. It may be possible to find completions to each of these strands separately by searching in different directions (with WLS or something similar). I tried this several years ago, but did not get very far.
Interestingly, my current knightship search (which has been running continuously for about 3 days) has also found exactly the same front as the one you mention. The current longest partial it has emitted is this one (about 2 hours ago, I estimate):

Code: Select all

x = 40, y = 53, rule = B3/S23
3b3o$3bo2bo$3bob2ob2o$2b2o7b2o$bo5bo4bo$bo5bob2o3bo$o5bo3bobobo$o4b2o
3bobobo$bo3bo3bo$bobobobo2bobo$8bobob2o$6b2o5bo2b2o$13b5o$10bo2bo4bo$
10bobob2o$9b2ob2o3b2o$12bo2b2o$12b2obobo$13bo2b2obo$10b2obo5bo$11b4ob
3o$15bo2bobo$18bobo$19b2o$11b3o5bo2bo$22bo$16b2o4bo$11bo4bo3bo$11b3o2b
obo$14bo2b3ob2o$11bo2bo2b4obo$19b2obo$12b3o7bo$12b2o3b2o$17b2o4b2o$15b
3obo5bo$15b2ob2o5bo$16b2obo6bo$18bo5bo2bo$19bo4bo2bo$19bob2o2bob2o$20b
3o4b2o$22bo5bo$20bo3b2obob3o$21b2o4b2o2bo$22bo2b2o2bobo$21bo4bo2bo3bo$
21bobob2o3b4o$21bob2ob2o6bo$22b3o2bo2bobo2b3o$22bo3bo7b4o$23bo2b2o2b2o
$24bob3o2b3o3b3o!
My search program uses a hybrid of David Eppstein's gfind methodology together with deep lookaheads using tom-iglucose (Tom Rokicki's interactive version of Marijn Heule's incremental version of Glucose 3.0).
What do you do with ill crystallographers? Take them to the mono-clinic!

User avatar
A for awesome
Posts: 2367
Joined: September 13th, 2014, 5:36 pm
Location: Pembina University, Home of the Gliders
Contact:

Re: Four new almost-knightships CGOL

Post by A for awesome » February 15th, 2018, 11:18 am

Note that the second almost-knightship in the original post trivially leads to another one with two cells difference:

Code: Select all

x = 24, y = 40, rule = B3/S23
3b2o$2b2o$4b2obo$2bo3b3ob2o$b6ob2o2bo$2ob2o4bo$o4bo6bobo$5o4b3o2bo$3ob
o4b2o$5b2o2bobo$bo3b2o3b2o$6bo3bo2bobo$9b3o2b3o$9b2obo$11bob3ob2o$9bo
2bo$8b2obo2bobo$8b2o2b3o$9bo2bo2bobo$9b2obob2o2b2o$11bob3o$17b3o$18b2o
2$10b2o6bo2bo$10b2obo4b4o$11b2o3b5o$11bo3b2o$11b2o4bo$11bo4b2o$9b5o2bo
2bo$12bo5b2o$11b2o6bob3o$12bo4b2o3b2o$15b4o$18b2o$19bo3bo$20b2o$21bo$
18b2o!
Also, has anyone tried searching for (2,1)c/7 using a similar approach?
praosylen#5847 (Discord)

The only decision I made was made
of flowers, to jump universes to one of springtime in
a land of former winter, where no invisible walls stood,
or could stand for more than a few hours at most...

User avatar
calcyman
Posts: 2418
Joined: June 1st, 2009, 4:32 pm

Re: Four new almost-knightships CGOL

Post by calcyman » February 15th, 2018, 12:41 pm

A for awesome wrote:Also, has anyone tried searching for (2,1)c/7 using a similar approach?
I'm in the process of modifying my search program to accept arbitrary velocities (a, b)c/p such that gcd(a, b, p) = 1. Then searching for p7 knightships and suchlike will be routine (although I imagine computationally harder than finding a p6 knightship).
What do you do with ill crystallographers? Take them to the mono-clinic!

User avatar
Macbi
Posts: 815
Joined: March 29th, 2009, 4:58 am

Re: Four new almost-knightships CGOL

Post by Macbi » February 15th, 2018, 12:45 pm

Obviously I can't tell anyone what to care about, but I think (2,1)c/7 ships are a bit less interesting than (2,1)c/6 ships, because it's already known that ships with speed (2,1)c/7 exist (with a much higher period). So a more interesting speed to search might be (3,1)c/8.

Gamedziner
Posts: 795
Joined: May 30th, 2016, 8:47 pm
Location: Milky Way Galaxy: Planet Earth

Re: Four new almost-knightships CGOL

Post by Gamedziner » February 15th, 2018, 6:16 pm

Is it possible to fuse any of these partials?

Code: Select all

x = 81, y = 96, rule = LifeHistory
58.2A$58.2A3$59.2A17.2A$59.2A17.2A3$79.2A$79.2A2$57.A$56.A$56.3A4$27.
A$27.A.A$27.2A21$3.2A$3.2A2.2A$7.2A18$7.2A$7.2A2.2A$11.2A11$2A$2A2.2A
$4.2A18$4.2A$4.2A2.2A$8.2A!

User avatar
77topaz
Posts: 1496
Joined: January 12th, 2018, 9:19 pm

Re: Four new almost-knightships CGOL

Post by 77topaz » February 15th, 2018, 6:27 pm

Gamedziner wrote:Is it possible to fuse any of these partials?
No, I don't think that would work, because all of these partials share the same front end. It's the fact that there isn't a stable (2,1)c/6 back end that's preventing the construction of a proper knightship. If there was a partial with a stable front end and a partial with a stable back end, then, sure, trying to fuse them could lead to a solution; however, with these partials it wouldn't be beneficial.

So, has anyone tried to search (or is it even possible to search) for a partial that has a stable back end, with any misalignments occurring at the front of the ship?

rokicki
Posts: 57
Joined: August 6th, 2009, 12:26 pm

Re: Four new almost-knightships CGOL

Post by rokicki » February 15th, 2018, 6:33 pm

I have tried to find a partial back end, and not been successful; for whatever reason my
programs are running so much slower for the back end. I do not know why; might be a bug.

The partials I have for the tail are so laughably small they are not worth posting (and the
bit error count is high too). But there *are* some partials (for some definition of partials).

Sokwe
Moderator
Posts: 1899
Joined: July 9th, 2009, 2:44 pm

Re: Four new almost-knightships CGOL

Post by Sokwe » February 15th, 2018, 7:37 pm

rokicki wrote:I have tried to find a partial back end, and not been successful; for whatever reason my
programs are running so much slower for the back end. I do not know why; might be a bug.
Searches for back ends always seem much slower, at least in Life. You will probably see this if you try running gfind with the 'r' parameter or searching for a spaceship from the back end with WLS. Of course, you might still have bugs in your program, but I would expect a reverse search to be slower even with a bug-free program.
-Matthias Merzenich

User avatar
77topaz
Posts: 1496
Joined: January 12th, 2018, 9:19 pm

Re: Four new almost-knightships CGOL

Post by 77topaz » February 15th, 2018, 7:50 pm

Hmm... the fact that back end searches are slower than front end ones might have to do with the fact that, when it is the front end that is stable, the stable part moves away from the instability, while with a stable back end the stable part moves towards the instability, and thus wouldn't last as long before being caught up in it. I can see why that would make it more difficult to find a stable back end.

AforAmpere
Posts: 1251
Joined: July 1st, 2016, 3:58 pm

Re: Four new almost-knightships CGOL

Post by AforAmpere » February 15th, 2018, 7:56 pm

Will these programs become public? Also, will they only work with glucose, or will they work with things like lingeling?
Wildmyron and I manage the 5S project, which collects all known spaceship speeds in Isotropic Non-totalistic rules.

Things to work on:
- Find a (7,1)c/8 ship in a Non-totalistic rule

rokicki
Posts: 57
Joined: August 6th, 2009, 12:26 pm

Re: Four new almost-knightships CGOL

Post by rokicki » February 15th, 2018, 11:41 pm

AforAmpere wrote:Will these programs become public? Also, will they only work with glucose, or will they work with things like lingeling?
You really don't want me to release them in their current state. They use the filesystem as a poor-man's database, creating literally millions of files, spawning hundreds of processes. They aren't tied to glucose other than we do use an incremental version of glucose that's been modified so we can make the subsequent subproblems depend on the solutions to the prior subproblems; most SAT solvers can probably be modified in similar ways or else a C API used.

Truly, most everything I'm doing you can do with a few Python scripts and the LLS program (though you do need changes to support incremental so you can pull more solutions more rapidly).

I suspect calcyman's code will be strictly more powerful and more useful than anything I've put together; I'm just trying some very opportunistic exploration of the space. But if something comes of this be assured I'll ensure others can duplicate the work, one way or the other.

rokicki
Posts: 57
Joined: August 6th, 2009, 12:26 pm

Re: Four new almost-knightships CGOL

Post by rokicki » February 16th, 2018, 11:42 am

Here are two related near-misses for (1,2)c/7:

Code: Select all

x = 11, y = 11, rule = B3/S23
3bo$2b3o$b3obo$2ob3o$bob2o$b3o4b3o$8bo$3b2o2b2o$3b2o4bo2$5bobo!

Code: Select all

x = 9, y = 13, rule = B3/S23
2bo$bobo$o3bo$o2b2o$3o$bo4bo$6bo$2bo$2bob3obo$b2obo3bo$4b2o$bo2bo$2bo!
And another near-miss; maybe somebody can complete it.

Code: Select all

x = 29, y = 23, rule = B3/S23
3bo$2b2o$b3o$2o2bobo$3b3o2bo$8b2o$5bo4b2obobobo$2b4ob2o6bobo$8bo3bo4bo
$15b2o$9b7o$8b2o$8b2o2b5ob3o$8b4o2b4o$12bo8bo$12b3ob2ob2o$14b2o3b7o$
15bobo3bo4bo$15bobo3bo2bo$26bo$23b3o$24b3obo$26bo!

User avatar
muzik
Posts: 4191
Joined: January 28th, 2016, 2:47 pm
Location: Scotland

Re: Four new almost-knightships CGOL

Post by muzik » December 13th, 2020, 6:26 am

Adam's new near-miss for c/7 knightwise (for those who don't use discord):

Code: Select all

x = 52, y = 13, rule = B3/S23
3b2ob2o34b2ob2o$2bo2b2o2bo31bo2b2o2bo$2bo7bo30bo7bo$bo3b2o3bo29bo3b2o
3bo$2b3ob2ob3o15bo13b3ob2ob3o$2bo3bo3bo18bo11bo3bo3bo$3bob7o7bobobobob
o3bo10bob7o$b2o2b3o21bo10b2o2b3o$2b2o3b2o18bo13b2o3b2o3bo$49bobo$o2bo
35bo2bo7bo$b4o35b4o$3b2o37b2o!

User avatar
A for awesome
Posts: 2367
Joined: September 13th, 2014, 5:36 pm
Location: Pembina University, Home of the Gliders
Contact:

Re: Four new almost-knightships CGOL

Post by A for awesome » December 13th, 2020, 11:27 am

muzik wrote:
December 13th, 2020, 6:26 am
Adam's new near-miss for c/7 knightwise (for those who don't use discord):

Code: Select all

rle
Here's a reasonable "canonical form" that's 1 cell off:

Code: Select all

x = 52, y = 13, rule = B3/S23
4bo38bo$3b6o33b6o$2b2o3b3o31b2o3b3o$2bo2b2obob2o29bo2b2obob2o$2b3obo2b
o17bo13b3obo2bo$12bo16bo21bo$2bob3o2bobo7bobobobobo3bo9bob3o2bobo$2bo
4b2obo18bo11bo4b2obo$2bo5b3obo14bo13bo5b3obo$obo7b2o27bobo7b3o$o38bo$
b3o36b3o$3b2o37b2o!
praosylen#5847 (Discord)

The only decision I made was made
of flowers, to jump universes to one of springtime in
a land of former winter, where no invisible walls stood,
or could stand for more than a few hours at most...

MathAndCode
Posts: 4615
Joined: August 31st, 2020, 5:58 pm

Re: Four new almost-knightships CGOL

Post by MathAndCode » December 13th, 2020, 3:54 pm

A for awesome wrote:
December 13th, 2020, 11:27 am
Here's a reasonable "canonical form" that's 1 cell off:

Code: Select all

x = 52, y = 13, rule = B3/S23
4bo38bo$3b6o33b6o$2b2o3b3o31b2o3b3o$2bo2b2obob2o29bo2b2obob2o$2b3obo2b
o17bo13b3obo2bo$12bo16bo21bo$2bob3o2bobo7bobobobobo3bo9bob3o2bobo$2bo
4b2obo18bo11bo4b2obo$2bo5b3obo14bo13bo5b3obo$obo7b2o27bobo7b3o$o38bo$
b3o36b3o$3b2o37b2o!
That looks promising because incorrect cell is at the very back, and the back part is a spark, which means that adding another section further back is less likely to mess the front section up, and the spark could help support a back section that otherwise wouldn't move forward at (2,1)c/7.
I have historically worked on conduits, but recently, I've been working on glider syntheses and investigating SnakeLife.

User avatar
A for awesome
Posts: 2367
Joined: September 13th, 2014, 5:36 pm
Location: Pembina University, Home of the Gliders
Contact:

Re: Four new almost-knightships CGOL

Post by A for awesome » January 22nd, 2021, 11:54 am

Here's another 1-cell-off (2,1)c/6 almost knightship from an ongoing search by Dylan Chen:

Code: Select all

x = 32, y = 51, rule = B3/S23
11bo$10b3o3bobobo$9b2o2b2o2bobob2o$10b3obobo4b3o$10b2o2b2o5b3o$10bob3o
3bo2b3o$10bo2bo4b2ob3o$5b2obo3bo5b5o$4b3o4b3o6bo$2b2o2bo2bob4o$2b2o$o
4bo2b6o$7o$b2o4bob2o2b3o$9b2obo$3bo4bo3bo3bo$7b2o3bo$6bo6b2ob2o$7b2o7b
obo$18bo$14b2o$13bo3b2o$13bo$12bo2bo$11b3o2b2o$17b3o$13bo2bo2b2o$23bo
bo$18b2o2bobobo$19b2obobobo$20bobobob2o$19bo3bob2o$21bob4obo$21bobobo
bo$21bob2obo$18b2o$19bobo4b2o$19bo$19bo$18b2ob2o$18b2o$17bo4bo$17bob3o
bo$18b7o2bo$19bo3b3ob2o$24b2obob2o2$27bo3bo$25bob4o$24b3o$26bo!
praosylen#5847 (Discord)

The only decision I made was made
of flowers, to jump universes to one of springtime in
a land of former winter, where no invisible walls stood,
or could stand for more than a few hours at most...

MathAndCode
Posts: 4615
Joined: August 31st, 2020, 5:58 pm

Re: Four new almost-knightships CGOL

Post by MathAndCode » January 22nd, 2021, 12:45 pm

A for awesome wrote:
January 22nd, 2021, 11:54 am
Here's another 1-cell-off (2,1)c/6 almost knightship from an ongoing search by Dylan Chen:
That is an incredibly powerful spark in the upper-right.
I have historically worked on conduits, but recently, I've been working on glider syntheses and investigating SnakeLife.

User avatar
calcyman
Posts: 2418
Joined: June 1st, 2009, 4:32 pm

Re: Four new almost-knightships CGOL

Post by calcyman » February 28th, 2021, 1:18 pm

A for awesome wrote:
January 22nd, 2021, 11:54 am
Here's another 1-cell-off (2,1)c/6 almost knightship from an ongoing search by Dylan Chen:

Code: Select all

x = 32, y = 51, rule = B3/S23
11bo$10b3o3bobobo$9b2o2b2o2bobob2o$10b3obobo4b3o$10b2o2b2o5b3o$10bob3o
3bo2b3o$10bo2bo4b2ob3o$5b2obo3bo5b5o$4b3o4b3o6bo$2b2o2bo2bob4o$2b2o$o
4bo2b6o$7o$b2o4bob2o2b3o$9b2obo$3bo4bo3bo3bo$7b2o3bo$6bo6b2ob2o$7b2o7b
obo$18bo$14b2o$13bo3b2o$13bo$12bo2bo$11b3o2b2o$17b3o$13bo2bo2b2o$23bo
bo$18b2o2bobobo$19b2obobobo$20bobobob2o$19bo3bob2o$21bob4obo$21bobobo
bo$21bob2obo$18b2o$19bobo4b2o$19bo$19bo$18b2ob2o$18b2o$17bo4bo$17bob3o
bo$18b7o2bo$19bo3b3ob2o$24b2obob2o2$27bo3bo$25bob4o$24b3o$26bo!
This is the longest partial I've managed to find so far (and no complete spaceships).

Code: Select all

#C depth = 995
#C breadth = 22
#CLL state-numbering golly
x = 148, y = 341, rule = B3/S23
12bo$11b4o4b3o$10bo2b2o2bo3bo$13bo2b2o$16b2ob2o$10b3o7bo$9b3o7b2o$
9b3o6bobo$4b3o$4b2ob2o2b2o$2bo3bo3b3ob3o$2b4ob2o4b2o$bo7b4o$3obo9b
o$2bo6b8o$6b2o3bo4bo$8b3o2bo$7bobo3bo2bobo$7bobo9bo$19bo$15b2o$15b
ob3o$13bo$13bob2o$12bo2bob2o$12bob5o$14bo2b2ob2o$22bo$18bo3bo$18bo
3b2o$23bo$20b2o$15b3ob2o3bo$15bo2b2o2bob3o$15bob2o3b2o$16bo5b2o$
14b2o4b2obo$14b3ob2o3bo$16b3o4b2obo$15bo7bobo$15bo3bobo$15bo4bobo$
17bo4bo$23bo$18b3obo$19bob3o$20bob2o$19bo$18bo3b2o$17b2o2b3o$22b2o
$16bo2bo$15bo3b2o$15bo4bobo$15bo3bo3bo$16bo7bo$17bobo2bo$22bo2bob
2o$17bo9b2o$17bobo2b2o3b2o$22b2o4bo$24bo2bobo$21b4o$21b6o2bo$28bo
2b2o$28bobobo$33bo$26bo5b2o$26bo6bo$26bo7bo$25bo4bob2o$24bo6bo$24b
o2bo4bobo$24b4o3bo2bo$29bo2bo$27bo2bobobo$24bo2bo3bo2b2o$24b4o3bob
o2bo$24b4o5b2o$28b3obob2o$25bo4b3ob2o$25bo3bob2ob2o$29bobo2b2o2$
29b2o2bo2b2o$29b2o2bo$35bo$35b3obo$33bob3o$34bobo3b2o$37bo2bo$37b
4o$37bobob2o$38bo$36b3o2b2o$41b2o$35b3o3bo$36bobobobo$36bo3b2o$41b
o$37bo2bo$37b2ob2o$37bob3o$36b2o3bo$35b2o3b2o$35bo3b2o$35b3o2bo2bo
$35b2o3bo3bo$38bo6bo$38bobob2obob2o$39b2o4bo$45b2o$38b2o2b4o$37b5o
3b2o$43bob2o$38bo4bo$39bo3bo2bo$41bob2obo$40b3o2bo$40b2ob2o$41bo5b
o$42b2o3bo$37b3o5bo$37bo8b2o$37bobo2$39b5o$40bobo$43bo$41b2o2b3o$
45bo2bo$46b3o$48b2ob2o$49bo3bo$49bo4bo$50bo2b2o$50bo$49b3o5b3o$49b
o4b2o$54b2o4bo$55bo4bo$56bo$57b2o$59b3o2$59b2obo$59bobobo$61bobo2b
3o$59bo3bo3b2o$60b2obob2o$63bobo$65bo$62b3o$62b3o$61b2o$61bo$60bo
3b2o$61bo2bo2$66b2o$65b3o$66b2o2b3o$65b2o3b4o$74bo$65bo4b3o$66bo7b
2o$66b2o2b2o$66bo2b3o2b2o$65b3o2b2ob3o$66bobobo$70b2obo$67b7o$72b
2o$76b2o$75b2obo$75b2obo$78bobo$78bobo$78bobo2$78bobo$78b2o2$77b3o
$76bo2bo$78bobo$78bo2$79bob3o$81b3o$80bob2o$80bo$80bo3b2o$80bo2bo
2b2obo$84bob2ob3o$87bo2b2o$84b3o4bo$84bo3bobobo$85b8o$93bo$85b6obo
bo$85bo4b3o$85b2o2bo2$94b2o$92b2ob3o$92b2o$95bobo$95b2o$92bo3bo$
93bo3bo$94bo2bo$96bo$98bo$96bo2bo$96bo3bo$95bo5bo$94b7obo$94bo7bo$
101bo$100b3o$96b4o3bo$96b2obo$97b2o$98b2o3bo$101b2obo$98b3obobo$
102bo2bo$102b2ob2o$100b3ob3o$100b2o2bo$99bo5bo$99bo2bo2bo$98bo3bo$
98b2obo$100b3o$97b2o2b2o$97bobo$98b3o$101bo$101b2obo$100bo3bo$103b
obo2$104b4o$104bo3bo$103b2o4bo$104b2o4b3o$105bobo5bo$105bo2bob2o$
106b2o$105bo2bo$105b2o$105bo2b2o$106b2obo$106b4o$107bo2bo$108b2o$
106b2o$110bo$105bo3bo2bo$106bo4b2o$106b2o3b3o$107bob2o2b2o$109bobo
$109b4obobobo$110b2o4bob2o$115b2o$116b2o$119b2o$116bo2b3o$121b2o$
117b2o2b2o$117b2o2b2o$116b3ob2o$118bobo2$119b2o$119b2o$119bo$118bo
$117b3o$117bo2b2ob4o$117bobobob2ob2o$118bo5b2o$118b2o2b4o$118bo5bo
$119b2o3bo$119bo$121b3o$121bo$121bo$121bobo2bo$124bob2o$122bo4bo$
129bobo$124bob3o$131b2obo$129bobob2o$128bo2bob2o$128bo4bo$133bo$
127b2o$127bob2obo$129b2o$127bo2bo$128bo$128bo3bo$129b2o2bo$130b2ob
2o$130bo3bo$132b4o$130b2o2b2o$132b3o$132bo3bobo$132b3obo2bo$132b2o
bo$132b3o2bo2bo$132b2obo4bo$131b2ob4o$138bobo$131bo4bobo2bo$134b3o
$138bo$133bo3b3o$132b4ob3obo$136bob3o$133b3o$131b2o6bo$131b2o3bo$
132b3obo2bo$133bobobo2b2o$134bob2o3b2o$132b3o2b3o$131bo2bo2bo5bo2$
133bo4b3ob2o$134b2o$133bo2bo4bob2o$135b2ob2obo2b2o$134b2o4bobo4bo!
What do you do with ill crystallographers? Take them to the mono-clinic!

wwei47
Posts: 765
Joined: February 18th, 2021, 11:18 am

Re: Four new almost-knightships CGOL

Post by wwei47 » February 28th, 2021, 1:21 pm

There are multiple thin connections there. Have you tried supporting it with a minstrel?
Let's all run dr on Herschels!

MathAndCode
Posts: 4615
Joined: August 31st, 2020, 5:58 pm

Re: Four new almost-knightships CGOL

Post by MathAndCode » February 28th, 2021, 1:40 pm

wwei47 wrote:
February 28th, 2021, 1:21 pm
There are multiple thin connections there. Have you tried supporting it with a minstrel?
The program could simply interpret that as the back of the spaceship, i.e. it doesn't differentiate between the two (at least not when searching for the first stabilization), so there is no need to look for that separately.
I have historically worked on conduits, but recently, I've been working on glider syntheses and investigating SnakeLife.

mscibing
Posts: 86
Joined: May 18th, 2010, 8:30 pm

Re: Four new almost-knightships CGOL

Post by mscibing » February 28th, 2021, 10:34 pm

Sokwe wrote:
February 14th, 2018, 2:05 am
I was originally interested in this partial, because it splits into two "strands" around rows 23 to 26. In your partials the strands quickly come back together to form a single strand again.
This sort of pattern is something I'm noticing in the (3,1)c/8 search. Here are a couple of partials with small voids in them:

Code: Select all

x = 20, y = 32, rule = B3/S23
8bo$7b4o$7bob2o$10bo$9bobo$5b2ob3o$6bo$4b2o4bob3o$3b2o4bo$2bobob2o7bo$
b3o8b2o2bo$2b2o12b2o$2b2o3bo7bo$2bo3bob2o7bo$2bobo12b2o$2b3o2b2o9b2o$
7b2o5bobob2o$6bo7bo4bo$6b2o$6b2o3bob2obo$6b2o3bob2o3bo$10bo5bobo$4bo2b
o2b2ob4o$9b2o$5b4o3bobo$4bobo3bobo$4bo10bo$3bo4bobo2b2obo$2b2o4bobo2b
2ob2o$2b6ob2o3bob2o$5bob4o$2o10bo!

Code: Select all

x = 18, y = 34, rule = B3/S23
7bo$6b4o$6bob2o$9bo$8bobo$4b2ob3o$5bo$3b2o4bob3o$2b2o4bo$bobob2o7bo$3o
8b2o2bo$b2o12b2o$b2o3bo8b2o$bo3bob2o4bobo$bobo8bo$b3o2b2o$6b2o4bo3bo$
6bo4b3o2b2o$3bo2bo2b2o2bob2o$3bo2b2o2bob4o$6b2o7bo$3b2ob2o3b2o$6bob2ob
o3bo$2bo3b4o3bo2bo$2bo2bo2bo4b5o$2bobob2o3bob2obo$3bo6bo4b2o$5b3o2bo3b
2o$8bobo3bo$4b5o5b2o$2b2o3b2o5bob2o$2b3o6bo2b2o$2bo2bo2bob2o2bobo$4b2o
3bobo3b2o!
And somewhat different, but I thought this partial interesting:

Code: Select all

x = 26, y = 22, rule = B3/S23
20bo$19b4o$9bo9bo3bo$8b3o12b2o$6b2o2bo9b2o3bo$6bo3b2o6bo2b2o$9bo11bob
2o$7bo2bob2o4b3o$7b2o2b3o2b2o3bo$7b2obo4bo3bobo$8bo2bobo7bo$13bo5bo$7b
o3bobo3b2o$6bo4bo4b2obo$5b4o3bob2o2bo$4bo3bo6bobobo$8b2o4bo3bo$3bo3bob
obob2o2bo$3b2obo5b3o$2bo2b2o2b2o$o2bo4b3o$4b3obo2b3o!
I tried taking advantage of this by allowing longer row lengths when there was a void at the end of a partial, but the strategy didn't pay off. (I only ran a small number of trials, but the cost in search time was significant, and the increase in maximum partial length was marginal. The results were not promising.)
-- Andrew Wade

User avatar
May13
Posts: 106
Joined: March 11th, 2021, 8:33 am

Re: Four new almost-knightships CGOL

Post by May13 » May 9th, 2021, 12:38 pm

MathAndCode wrote:
January 22nd, 2021, 12:45 pm
That is an incredibly powerful spark in the upper-right.
That can support wandering and wandering+connecting minstrels (what their numbers are?):

Code: Select all

x = 143, y = 105, rule = B3/S23
10$89b3o$88bo2b2o3b5o$88bo4bob4o3bo$16b3o72bo3bo$15bo2b2o3b5o60bo10bo
3bo$15bo4bob4o3bo58b2obo2bo2b2o4bo$18bo3bo65bo4bo2bo$15bo10bo3bo52bob
2o10bo4bob3o$15b2obo2bo2b2o4bo51b2o5bo3bo5bo4bo$15bo4bo2bo57bo3bo3b2o
2bo10bo2bo$10bob2o10bo4bob3o46b4o3bo5bo11bobob2o$9b2o5bo3bo5bo4bo47bo
4b2o2b4o15bo$8bo3bo3b2o2bo10bo2bo44bo2b5o19bobob2o$7b4o3bo5bo11bobob2o
41bo3b3ob4ob2o13bo3bo$6bo4b2o2b4o15bo46bo7bobob2o13bo$6bo2b5o19bobob2o
47b2o3b2o$6bo3b3ob4ob2o13bo3bo47b2o3bo2b3o$8bo7bobob2o13bo49bo6bob3o
14b2o$13b2o3b2o66bo7b2obo14bo$13b2o3bo2b3o70bobo12b2ob2o$12bo6bob3o69b
o2b2o11bo2b2o$13bo7b2obo67bo15bo3bo$21bobo67b3o14b2o$20bo2b2o65bo2bobo
12b3obo$19bo70b3o2b2o13bob2o$18b3o71bo5b2o10bobo$17bo2bobo73bob2o10bo
3bo$17b3o2b2o73bobo2b3o6bo3b2o$19bo5b2o70b5obobo6b2ob2o$23bob2o70bobob
obobo9bo$24bobo2b3o67bobobo2bo7b3o$24b5obobo66b2o16b2o$24bobobobobo66b
o2bo$26bobobo2bo65b2o5bo$26b2o71bo2b4o$26bo2bo67b2o2bo2b3o10b5o$26b2o
5bo64bo18b4o$26bo2b4o64b2o18bob2o$24b2o2bo2b3o64bo17bo2bo$25bo89bo5bo$
24b2o70bob4o14bo4b2o$25bo70bo3b2o15bob2ob2o$96bo6bo18b2o$23bob4o75b4o
13b2o$23bo3b2o68b2obo5bobo11b2o$23bo6bo71bobobobo11bo$31b4o70bobobo$
24b2obo5bobo69b2ob2o12bo$29bobobobo67b2ob4o11bobo$32bobobo66bo3b2o11b
2ob2o$32b2ob2o68bo14b2obo$30b2ob4o83b2obo$30bo3b2o84bo2bo$32bo86bob3o$
118bo4bo3bo$123b2obobo$123bo2bobo$120b3o2b2o$124bobo$124bobo$124bo$
124b2o2bo$127bo$127b2o$124b2o2b2o$124bobobo$126bobo$128bo$127bo$126bo
2b3o$126b5o$125bob2o$126bo2$126bobo$126b3obo$130bo$125b2o$124b2o$126bo
2bo$127bo!
[[ THEME 0 LOOP 12 TRACK -1/6 -1/3 ]]
calcyman wrote:
February 28th, 2021, 1:18 pm
This is the longest partial I've managed to find so far (and no complete spaceships).

Code: Select all

#C depth = 995
#C breadth = 22
#CLL state-numbering golly
x = 148, y = 341, rule = B3/S23
12bo$11b4o4b3o$10bo2b2o2bo3bo$13bo2b2o$16b2ob2o$10b3o7bo$9b3o7b2o$
9b3o6bobo$4b3o$4b2ob2o2b2o$2bo3bo3b3ob3o$2b4ob2o4b2o$bo7b4o$3obo9b
o$2bo6b8o$6b2o3bo4bo$8b3o2bo$7bobo3bo2bobo$7bobo9bo$19bo$15b2o$15b
ob3o$13bo$13bob2o$12bo2bob2o$12bob5o$14bo2b2ob2o$22bo$18bo3bo$18bo
3b2o$23bo$20b2o$15b3ob2o3bo$15bo2b2o2bob3o$15bob2o3b2o$16bo5b2o$
14b2o4b2obo$14b3ob2o3bo$16b3o4b2obo$15bo7bobo$15bo3bobo$15bo4bobo$
17bo4bo$23bo$18b3obo$19bob3o$20bob2o$19bo$18bo3b2o$17b2o2b3o$22b2o
$16bo2bo$15bo3b2o$15bo4bobo$15bo3bo3bo$16bo7bo$17bobo2bo$22bo2bob
2o$17bo9b2o$17bobo2b2o3b2o$22b2o4bo$24bo2bobo$21b4o$21b6o2bo$28bo
2b2o$28bobobo$33bo$26bo5b2o$26bo6bo$26bo7bo$25bo4bob2o$24bo6bo$24b
o2bo4bobo$24b4o3bo2bo$29bo2bo$27bo2bobobo$24bo2bo3bo2b2o$24b4o3bob
o2bo$24b4o5b2o$28b3obob2o$25bo4b3ob2o$25bo3bob2ob2o$29bobo2b2o2$
29b2o2bo2b2o$29b2o2bo$35bo$35b3obo$33bob3o$34bobo3b2o$37bo2bo$37b
4o$37bobob2o$38bo$36b3o2b2o$41b2o$35b3o3bo$36bobobobo$36bo3b2o$41b
o$37bo2bo$37b2ob2o$37bob3o$36b2o3bo$35b2o3b2o$35bo3b2o$35b3o2bo2bo
$35b2o3bo3bo$38bo6bo$38bobob2obob2o$39b2o4bo$45b2o$38b2o2b4o$37b5o
3b2o$43bob2o$38bo4bo$39bo3bo2bo$41bob2obo$40b3o2bo$40b2ob2o$41bo5b
o$42b2o3bo$37b3o5bo$37bo8b2o$37bobo2$39b5o$40bobo$43bo$41b2o2b3o$
45bo2bo$46b3o$48b2ob2o$49bo3bo$49bo4bo$50bo2b2o$50bo$49b3o5b3o$49b
o4b2o$54b2o4bo$55bo4bo$56bo$57b2o$59b3o2$59b2obo$59bobobo$61bobo2b
3o$59bo3bo3b2o$60b2obob2o$63bobo$65bo$62b3o$62b3o$61b2o$61bo$60bo
3b2o$61bo2bo2$66b2o$65b3o$66b2o2b3o$65b2o3b4o$74bo$65bo4b3o$66bo7b
2o$66b2o2b2o$66bo2b3o2b2o$65b3o2b2ob3o$66bobobo$70b2obo$67b7o$72b
2o$76b2o$75b2obo$75b2obo$78bobo$78bobo$78bobo2$78bobo$78b2o2$77b3o
$76bo2bo$78bobo$78bo2$79bob3o$81b3o$80bob2o$80bo$80bo3b2o$80bo2bo
2b2obo$84bob2ob3o$87bo2b2o$84b3o4bo$84bo3bobobo$85b8o$93bo$85b6obo
bo$85bo4b3o$85b2o2bo2$94b2o$92b2ob3o$92b2o$95bobo$95b2o$92bo3bo$
93bo3bo$94bo2bo$96bo$98bo$96bo2bo$96bo3bo$95bo5bo$94b7obo$94bo7bo$
101bo$100b3o$96b4o3bo$96b2obo$97b2o$98b2o3bo$101b2obo$98b3obobo$
102bo2bo$102b2ob2o$100b3ob3o$100b2o2bo$99bo5bo$99bo2bo2bo$98bo3bo$
98b2obo$100b3o$97b2o2b2o$97bobo$98b3o$101bo$101b2obo$100bo3bo$103b
obo2$104b4o$104bo3bo$103b2o4bo$104b2o4b3o$105bobo5bo$105bo2bob2o$
106b2o$105bo2bo$105b2o$105bo2b2o$106b2obo$106b4o$107bo2bo$108b2o$
106b2o$110bo$105bo3bo2bo$106bo4b2o$106b2o3b3o$107bob2o2b2o$109bobo
$109b4obobobo$110b2o4bob2o$115b2o$116b2o$119b2o$116bo2b3o$121b2o$
117b2o2b2o$117b2o2b2o$116b3ob2o$118bobo2$119b2o$119b2o$119bo$118bo
$117b3o$117bo2b2ob4o$117bobobob2ob2o$118bo5b2o$118b2o2b4o$118bo5bo
$119b2o3bo$119bo$121b3o$121bo$121bo$121bobo2bo$124bob2o$122bo4bo$
129bobo$124bob3o$131b2obo$129bobob2o$128bo2bob2o$128bo4bo$133bo$
127b2o$127bob2obo$129b2o$127bo2bo$128bo$128bo3bo$129b2o2bo$130b2ob
2o$130bo3bo$132b4o$130b2o2b2o$132b3o$132bo3bobo$132b3obo2bo$132b2o
bo$132b3o2bo2bo$132b2obo4bo$131b2ob4o$138bobo$131bo4bobo2bo$134b3o
$138bo$133bo3b3o$132b4ob3obo$136bob3o$133b3o$131b2o6bo$131b2o3bo$
132b3obo2bo$133bobobo2b2o$134bob2o3b2o$132b3o2b3o$131bo2bo2bo5bo2$
133bo4b3ob2o$134b2o$133bo2bo4bob2o$135b2ob2obo2b2o$134b2o4bobo4bo!
:idea: calcyman, your partial is infinitely extensible!

Code: Select all

x = 185, y = 985, rule = B3/S23
5$19b2o7b2o$18b2o3b3ob3o$20b2o2b2obobo$19bob2o5b2o$19b2ob5ob2o$19b2o5b
o2bo$18bo8b3o$13b3ob2o9b2o$11b2ob2obo2b2o$11b5o2bob2obo$9bo7b3o3bo$9b
7o6bo$8bo4bo2b4o2b2o$10b3o9bo$9b3o7b4o$17bo5b3o$14b3o$26bo2$24b2obo$
22b2obo$22bo4bo$21bo$20b4o$20bob4o$22bo3b2o$21b2o2bob2o$25bobo2bo$26bo
2bo$31bo$29bobo$23b3o2b2ob2o$22bo2bobo3b3o$22bo4b4o2bo$25b3ob3obo$22bo
6b5o$21b2ob2o3b4o$21b3obo$22b2o4b2o$25b2obo$22bo4b2o$24bo3bo$27bo$26bo
4bo$25bo2b3o$26bo$26b3o$29bo$25bobobo$24bo4bob2o$25bo3b2o$24b2o4bo$22b
obo$22bo2bobob2o$22bo7bo$23b3o4b3o$25bo9bo$30b2o3b2o$25b3o2b2o3bobo$
29bo2bo3b3o$29b2obo3b2o$29b3obob3o$28b3o2bobo$29bobobo2b2obo$30b5ob6o$
31b2o3b2o3bo$39bo$34bo4bo$33bobo3bo3bo$32bo2bo6bo$39bobo$31bob2o3bo$
31bo3b2obo2bo$31bo5b2o$32b2o4bobo$34bo3bobob2o$35b2ob3o2bo$31b2o2b2o3b
obo$31b2o2bo3b2o$35bo$35bo2bo$40b3obo$38bob2o$37bob2o3bo$36bo5bobo$37b
2o3bo$42b4o$45b3o$45b2ob2o$45bob3o$43b3o$46bo$45b2obo$44bo2b2obo$44b3o
2bo$43bo2bobo$43b4obo$45bo$46b2o2bo$45bo3bo$44b5o$44b2o2bo$47bo$45bobo
b2o$42b2obobo$42b2obobobo$42b3o2b2o$44bobo2b2ob2o$46b2ob2o2b2o$46bo6bo
$46bo3bob2o$46bo4b2obo$45b3o3bo$44b3obo2bo$48bob5o$49b3o2$50b2o2bo$50b
o2bo$34b3o14b3o$33bo2b2o3b5o3b2ob2o$33bo4bob4o3bobo$36bo3bo13b2o$33bo
10bo3bo$33b2obo2bo2b2o4bo$33bo4bo2bo$28bob2o10bo4bo$27b2o5bo3bo5bo$26b
o3bo3b2o2bo$25b4o3bo5bo$24bo4b2o2b4o$24bo2b5o$24bo3b3ob4ob2o$26bo7bobo
b2o$31b2o3b2o$31b2o3bo2b3o$30bo6bob3o$31bo7b2obo$39bobo$38bo2b2o$37bo$
36b3o$35bo2bobo$35b3o2b2o$37bo5b2o$41bob2o$42bo2bo$42b4o$42b2o2bo$43bo
2bo$39b2o2bo$38b2o2bo3bob2o$40bo2b3o2b2o$38bo2bob2o2b2o$38bo4bo3b2o$
37bo4bo4b3o$38bob2o5b3o$40bo4bo$38b3o4bo$38b2ob3o$41b2ob2o$42bob2o$41b
3obo2$45b2o$42b4o$42b2obo$41bo3bo$40b2o4bo$40b3o3bo$39bo2bo$38b3o3bo$
37bo2b2o2bobo$40bob4obo$37bo2b3o2bobo$38bobo5b3o2bo$40b3o3bo3b2o$40bo
3b3o$41bo9bo$47bo2bobo$43bob3o2b2o$44bo3b2ob2o$51bo2bo$51bob3o$50b2o2b
o$50b2o2b2obo$50b5o2bo$50b5o$49bobo3b3o$48b3o4bo$47b3o5b3o$56bo$46bo3b
2obobo$46bo6bobobo$51b2obo2b3o$47b2ob3obobo$48bo3bobobo2bo$51b2o4bo$
47bo2bo4bobo$48b5ob2obo$50b2o4b2o$55b2o2bo$53b4o3bo$52b2o5bo$55bo$57b
2o2b2o$56b3ob3o$61bob2o$60bo2bobo$60b2obo$64bo$60bobob2o$59bo2bob2o$
59bo$65bo$58b2obobobo$60b2ob2o$61b2o$60bo2bo$61bobo$60bo2bo$59bo4bo$
59bo3b2o$58bo4bo$58b2o3bo$59bobobob3o$61bob4obobo$61b3o3b2obo$68bobo$
64bobo$61bo5b2o$61b2o2bo2bo$60bo2b2o3bo$62b5obo$62b2o2b4o$64bo4bo$64b
2o$64bo2b2o$50b2o7b2o3bo2b4o$49b2o3b3ob3o4b2obobo$51b2o2b2obobo8bo$50b
ob2o5b2o8b2o$50b2ob5ob2o$50b2o5bo2bo$49bo8b3o$44b3ob2o9b2o$42b2ob2obo
2b2o$42b5o2bob2obo$40bo7b3o3bo$40b7o6bo$39bo4bo2b4o2b2o$41b3o9bo$40b3o
7b4o$48bo5b3o$45b3o$57bo2$55b2obo$53b2obo$53bo4bo$52bo$51b4o$51bob4o$
53bo3b2o$52b2o2bob2o$56bobo2bo$57bo2bo$62bo$60bobo$54b3o2b2ob2o$53bo2b
obo3b3o$53bo4b4o2bo$56b3ob3obo$53bo6b5o$52b2ob2o3b4o$52b3obo$53b2o4b2o
$56b2obo$53bo4b2o$55bo3bo$58bo$57bo4bo$56bo2b3o$57bo$57b3o$60bo$56bobo
bo$55bo4bob2o$56bo3b2o$55b2o4bo$53bobo$53bo2bobob2o$53bo7bo$54b3o4b3o$
56bo9bo$61b2o3b2o$56b3o2b2o3bobo$60bo2bo3b3o$60b2obo3b2o$60b3obob3o$
59b3o2bobo$60bobobo2b2obo$61b5ob6o$62b2o3b2o3bo$70bo$65bo4bo$64bobo3bo
3bo$63bo2bo6bo$70bobo$62bob2o3bo$62bo3b2obo2bo$62bo5b2o$63b2o4bobo$65b
o3bobob2o$66b2ob3o2bo$62b2o2b2o3bobo$62b2o2bo3b2o$66bo$66bo2bo$71b3obo
$69bob2o$68bob2o3bo$67bo5bobo$68b2o3bo$73b4o$76b3o$76b2ob2o$76bob3o$
74b3o$77bo$76b2obo$75bo2b2obo$75b3o2bo$74bo2bobo$74b4obo$76bo$77b2o2bo
$76bo3bo$75b5o$75b2o2bo$78bo$76bobob2o$73b2obobo$73b2obobobo$73b3o2b2o
$75bobo2b2ob2o$77b2ob2o2b2o$77bo6bo$77bo3bob2o$77bo4b2obo$76b3o3bo$75b
3obo2bo$79bob5o$80b3o2$81b2o2bo$81bo2bo$65b3o14b3o$64bo2b2o3b5o3b2ob2o
$64bo4bob4o3bobo$67bo3bo13b2o$64bo10bo3bo$64b2obo2bo2b2o4bo$64bo4bo2bo
$59bob2o10bo4bo$58b2o5bo3bo5bo$57bo3bo3b2o2bo$56b4o3bo5bo$55bo4b2o2b4o
$55bo2b5o$55bo3b3ob4ob2o$57bo7bobob2o$62b2o3b2o$62b2o3bo2b3o$61bo6bob
3o$62bo7b2obo$70bobo$69bo2b2o$68bo$67b3o$66bo2bobo$66b3o2b2o$68bo5b2o$
72bob2o$73bo2bo$73b4o$73b2o2bo$74bo2bo$70b2o2bo$69b2o2bo3bob2o$71bo2b
3o2b2o$69bo2bob2o2b2o$69bo4bo3b2o$68bo4bo4b3o$69bob2o5b3o$71bo4bo$69b
3o4bo$69b2ob3o$72b2ob2o$73bob2o$72b3obo2$76b2o$73b4o$73b2obo$72bo3bo$
71b2o4bo$71b3o3bo$70bo2bo$69b3o3bo$68bo2b2o2bobo$71bob4obo$68bo2b3o2bo
bo$69bobo5b3o2bo$71b3o3bo3b2o$71bo3b3o$72bo9bo$78bo2bobo$74bob3o2b2o$
75bo3b2ob2o$82bo2bo$82bob3o$81b2o2bo$81b2o2b2obo$81b5o2bo$81b5o$80bobo
3b3o$79b3o4bo$78b3o5b3o$87bo$77bo3b2obobo$77bo6bobobo$82b2obo2b3o$78b
2ob3obobo$79bo3bobobo2bo$82b2o4bo$78bo2bo4bobo$79b5ob2obo$81b2o4b2o$
86b2o2bo$84b4o3bo$83b2o5bo$86bo$88b2o2b2o$87b3ob3o$92bob2o$91bo2bobo$
91b2obo$95bo$91bobob2o$90bo2bob2o$90bo$96bo$89b2obobobo$91b2ob2o$92b2o
$91bo2bo$92bobo$91bo2bo$90bo4bo$90bo3b2o$89bo4bo$89b2o3bo$90bobobob3o$
92bob4obobo$92b3o3b2obo$99bobo$95bobo$92bo5b2o$92b2o2bo2bo$91bo2b2o3bo
$93b5obo$93b2o2b4o$95bo4bo$95b2o$95bo2b2o$81b2o7b2o3bo2b4o$80b2o3b3ob
3o4b2obobo$82b2o2b2obobo8bo$81bob2o5b2o8b2o$81b2ob5ob2o$81b2o5bo2bo$
80bo8b3o$75b3ob2o9b2o$73b2ob2obo2b2o$73b5o2bob2obo$71bo7b3o3bo$71b7o6b
o$70bo4bo2b4o2b2o$72b3o9bo$71b3o7b4o$79bo5b3o$76b3o$88bo2$86b2obo$84b
2obo$84bo4bo$83bo$82b4o$82bob4o$84bo3b2o$83b2o2bob2o$87bobo2bo$88bo2bo
$93bo$91bobo$85b3o2b2ob2o$84bo2bobo3b3o$84bo4b4o2bo$87b3ob3obo$84bo6b
5o$83b2ob2o3b4o$83b3obo$84b2o4b2o$87b2obo$84bo4b2o$86bo3bo$89bo$88bo4b
o$87bo2b3o$88bo$88b3o$91bo$87bobobo$86bo4bob2o$87bo3b2o$86b2o4bo$84bob
o$84bo2bobob2o$84bo7bo$85b3o4b3o$87bo9bo$92b2o3b2o$87b3o2b2o3bobo$91bo
2bo3b3o$91b2obo3b2o$91b3obob3o$90b3o2bobo$91bobobo2b2obo$92b5ob6o$93b
2o3b2o3bo$101bo$96bo4bo$95bobo3bo3bo$94bo2bo6bo$101bobo$93bob2o3bo$93b
o3b2obo2bo$93bo5b2o$94b2o4bobo$96bo3bobob2o$97b2ob3o2bo$93b2o2b2o3bobo
$93b2o2bo3b2o$97bo$97bo2bo$102b3obo$100bob2o$99bob2o3bo$98bo5bobo$99b
2o3bo$104b4o$107b3o$107b2ob2o$107bob3o$105b3o$108bo$107b2obo$106bo2b2o
bo$106b3o2bo$105bo2bobo$105b4obo$107bo$108b2o2bo$107bo3bo$106b5o$106b
2o2bo$109bo$107bobob2o$104b2obobo$104b2obobobo$104b3o2b2o$106bobo2b2ob
2o$108b2ob2o2b2o$108bo6bo$108bo3bob2o$108bo4b2obo$107b3o3bo$106b3obo2b
o$110bob5o$111b3o2$112b2o2bo$112bo2bo$96b3o14b3o$95bo2b2o3b5o3b2ob2o$
95bo4bob4o3bobo$98bo3bo13b2o$95bo10bo3bo$95b2obo2bo2b2o4bo$95bo4bo2bo$
90bob2o10bo4bo$89b2o5bo3bo5bo$88bo3bo3b2o2bo$87b4o3bo5bo$86bo4b2o2b4o$
86bo2b5o$86bo3b3ob4ob2o$88bo7bobob2o$93b2o3b2o$93b2o3bo2b3o$92bo6bob3o
$93bo7b2obo$101bobo$100bo2b2o$99bo$98b3o$97bo2bobo$97b3o2b2o$99bo5b2o$
103bob2o$104bo2bo$104b4o$104b2o2bo$105bo2bo$101b2o2bo$100b2o2bo3bob2o$
102bo2b3o2b2o$100bo2bob2o2b2o$100bo4bo3b2o$99bo4bo4b3o$100bob2o5b3o$
102bo4bo$100b3o4bo$100b2ob3o$103b2ob2o$104bob2o$103b3obo2$107b2o$104b
4o$104b2obo$103bo3bo$102b2o4bo$102b3o3bo$101bo2bo$100b3o3bo$99bo2b2o2b
obo$102bob4obo$99bo2b3o2bobo$100bobo5b3o2bo$102b3o3bo3b2o$102bo3b3o$
103bo9bo$109bo2bobo$105bob3o2b2o$106bo3b2ob2o$113bo2bo$113bob3o$112b2o
2bo$112b2o2b2obo$112b5o2bo$112b5o$111bobo3b3o$110b3o4bo$109b3o5b3o$
118bo$108bo3b2obobo$108bo6bobobo$113b2obo2b3o$109b2ob3obobo$110bo3bobo
bo2bo$113b2o4bo$109bo2bo4bobo$110b5ob2obo$112b2o4b2o$117b2o2bo$115b4o
3bo$114b2o5bo$117bo$119b2o2b2o$118b3ob3o$123bob2o$122bo2bobo$122b2obo$
126bo$122bobob2o$121bo2bob2o$121bo$127bo$120b2obobobo$122b2ob2o$123b2o
$122bo2bo$123bobo$122bo2bo$121bo4bo$121bo3b2o$120bo4bo$120b2o3bo$121bo
bobob3o$123bob4obobo$123b3o3b2obo$130bobo$126bobo$123bo5b2o$123b2o2bo
2bo$122bo2b2o3bo$124b5obo$124b2o2b4o$126bo4bo$126b2o$126bo2b2o$112b2o
7b2o3bo2b4o$111b2o3b3ob3o4b2obobo$113b2o2b2obobo8bo$112bob2o5b2o8b2o$
112b2ob5ob2o$112b2o5bo2bo$111bo8b3o$106b3ob2o9b2o$104b2ob2obo2b2o$104b
5o2bob2obo$102bo7b3o3bo$102b7o6bo$101bo4bo2b4o2b2o$103b3o9bo$102b3o7b
4o$110bo5b3o$107b3o$119bo2$117b2obo$115b2obo$115bo4bo$114bo$113b4o$
113bob4o$115bo3b2o$114b2o2bob2o$118bobo2bo$119bo2bo$124bo$122bobo$116b
3o2b2ob2o$115bo2bobo3b3o$115bo4b4o2bo$118b3ob3obo$115bo6b5o$114b2ob2o
3b4o$114b3obo$115b2o4b2o$118b2obo$115bo4b2o$117bo3bo$120bo$119bo4bo$
118bo2b3o$119bo$119b3o$122bo$118bobobo$117bo4bob2o$118bo3b2o$117b2o4bo
$115bobo$115bo2bobob2o$115bo7bo$116b3o4b3o$118bo9bo$123b2o3b2o$118b3o
2b2o3bobo$122bo2bo3b3o$122b2obo3b2o$122b3obob3o$121b3o2bobo$122bobobo
2b2obo$123b5ob6o$124b2o3b2o3bo$132bo$127bo4bo$126bobo3bo3bo$125bo2bo6b
o$132bobo$124bob2o3bo$124bo3b2obo2bo$124bo5b2o$125b2o4bobo$127bo3bobob
2o$128b2ob3o2bo$124b2o2b2o3bobo$124b2o2bo3b2o$128bo$128bo2bo$133b3obo$
131bob2o$130bob2o3bo$129bo5bobo$130b2o3bo$135b4o$138b3o$138b2ob2o$138b
ob3o$136b3o$139bo$138b2obo$137bo2b2obo$137b3o2bo$136bo2bobo$136b4obo$
138bo$139b2o2bo$138bo3bo$137b5o$137b2o2bo$140bo$138bobob2o$135b2obobo$
135b2obobobo$135b3o2b2o$137bobo2b2ob2o$139b2ob2o2b2o$139bo6bo$139bo3bo
b2o$139bo4b2obo$138b3o3bo$137b3obo2bo$141bob5o$142b3o2$143b2o2bo$143bo
2bo$127b3o14b3o$126bo2b2o3b5o3b2ob2o$126bo4bob4o3bobo$129bo3bo13b2o$
126bo10bo3bo$126b2obo2bo2b2o4bo$126bo4bo2bo$121bob2o10bo4bo$120b2o5bo
3bo5bo$119bo3bo3b2o2bo$118b4o3bo5bo$117bo4b2o2b4o$117bo2b5o$117bo3b3ob
4ob2o$119bo7bobob2o$124b2o3b2o$124b2o3bo2b3o$123bo6bob3o$124bo7b2obo$
132bobo$131bo2b2o$130bo$129b3o$128bo2bobo$128b3o2b2o$130bo5b2o$134bob
2o$135bo2bo$135b4o$135b2o2bo$136bo2bo$132b2o2bo$131b2o2bo3bob2o$133bo
2b3o2b2o$131bo2bob2o2b2o$131bo4bo3b2o$130bo4bo4b3o$131bob2o5b3o$133bo
4bo$131b3o4bo$131b2ob3o$134b2ob2o$135bob2o$134b3obo2$138b2o$135b4o$
135b2obo$134bo3bo$133b2o4bo$133b3o3bo$132bo2bo$131b3o3bo$130bo2b2o2bob
o$133bob4obo$130bo2b3o2bobo$131bobo5b3o2bo$133b3o3bo3b2o$133bo3b3o$
134bo9bo$140bo2bobo$136bob3o2b2o$137bo3b2ob2o$144bo2bo$144bob3o$143b2o
2bo$143b2o2b2obo$143b5o2bo$143b5o$142bobo3b3o$141b3o4bo$140b3o5b3o$
149bo$139bo3b2obobo$139bo6bobobo$144b2obo2b3o$140b2ob3obobo$141bo3bobo
bo2bo$144b2o4bo$140bo2bo4bobo$141b5ob2obo$143b2o4b2o$148b2o2bo$146b4o
3bo$145b2o5bo$148bo$150b2o2b2o$149b3ob3o$154bob2o$153bo2bobo$153b2obo$
157bo$153bobob2o$152bo2bob2o$152bo$158bo$151b2obobobo$153b2ob2o$154b2o
$153bo2bo$154bobo$153bo2bo$152bo4bo$152bo3b2o$151bo4bo$151b2o3bo$152bo
bobob3o$154bob4obobo$154b3o3b2obo$161bobo$157bobo$154bo5b2o$154b2o2bo
2bo$153bo2b2o3bo$155b5obo$155b2o2b4o$157bo4bo$157b2o$157bo2b2o$143b2o
7b2o3bo2b4o$142b2o3b3ob3o4b2obobo$144b2o2b2obobo8bo$143bob2o5b2o8b2o$
143b2ob5ob2o$143b2o5bo2bo$142bo8b3o$137b3ob2o9b2o$135b2ob2obo2b2o$135b
5o2bob2obo$133bo7b3o3bo$133b7o6bo$132bo4bo2b4o2b2o$134b3o9bo$133b3o7b
4o$141bo5b3o$138b3o$150bo!
[[ TRACK -1/6 -1/3 ]]
How much time did you spend on this? And what is the width?
I am also interested in finding new oblique spaceships using ikpx 2.2.

Post Reply