Ridiculous baseline, (1,0)c/3, 7:
Code: Select all
x = 3, y = 2, rule = B2-cn3e/S2c3i
bo$obo!
(1,1)c/6, 7:
Code: Select all
x = 2, y = 3, rule = B2ce/S12aek
o$bo$bo!
Even more ridiculous, (1,1)c/8, 10:
Code: Select all
x = 4, y = 3, rule = B2ce3aijqr/S02ak
o$3bo$bobo!
(1,1)c/7, 10:
Code: Select all
x = 2, y = 4, rule = B2ce3aiqr/S02aek
bo$o2$bo!
Less ridiculous HuntingFinds:
(2,0)c/6, 5:
Code: Select all
x = 2, y = 3, rule = B2ce3n/S1
o$bo$bo!
(1,0)c/4, 9:
Code: Select all
x = 5, y = 2, rule = B2ek3ai4i5y/S03jk
2bo$o3bo!
(1,0)c/5, 9:
Code: Select all
x = 5, y = 2, rule = B2ek3i4i/S02a3j4iw
2bo$o3bo!
(4,0)c/8, 5:
Code: Select all
x = 5, y = 2, rule = B2ck3ai/S0
2bo$o3bo!
Meanwhile, directly optimizing the rule, (3,0)c/6, 5:
Code: Select all
x = 2, y = 8, rule = B2ce3n/S1
bo$o$bo3$bo$o$bo!
(10,0)c/24, 5:
Code: Select all
x = 14, y = 11, rule = B2ce3c/S1
o2bo6bo2bo$6b2o$o2bo6bo2bo2$13bo2$13bo2$o2bo6bo2bo$6b2o$o2bo6bo2bo!
I tried looking for (2,1)c/6s. Obviously no luck. 15:
Code: Select all
x = 3, y = 3, rule = B2ce3aiq4j/S012cek3jq5i
2bo$o$o!
(2,1)c/3, 15:
Code: Select all
x = 7, y = 3, rule = B2ac3q4an5kn/S1e3ar4iqr5ij
o2bo2bo$b2o$b5o!
I tried my best.
EDIT: (1, 1)c/2, 9:
Code: Select all
x = 4, y = 4, rule = B2a3a4r6e/S02e3ir4q
o2bo$b2o$b3o$obo!
EDIT: (2, 0)c/3, 10:
Code: Select all
x = 5, y = 3, rule = B2ack3ey/S02-ei
o3bo$bobo$bobo!
EDIT: (2, 0)c/2, 2:
Code: Select all
x = 2, y = 3, rule = B2ae/S
o$bo$bo!
EDIT: (1, 1)c/2 can be done with 8 transistions:
Code: Select all
x = 3, y = 3, rule = B2a3a4r5c/S3ai4er
3o$b2o$obo!
I'm not familiar with B2a rules, maybe someone can do better than me.