For discussion of specific patterns or specific families of patterns, both newly-discovered and well-known.

All matter of useless Life patterns go here. For example, the following is a methuselah that takes 946 generations to stabilise:
`x = 10, y = 3, rule = B3/S233o6bo\$obo4b3o\$obo6bo!`

Have fun.
Princess of Science, Parcly Taxel

Freywa

Posts: 518
Joined: June 23rd, 2011, 3:20 am
Location: Singapore

This pattern makes (two copies of) a traffic light by creating each blinker separately.
`x = 25, y = 25, rule = B3/S23b2o\$o2bo\$o3bo\$bo3bo\$2bo3bo\$3bo3bo\$4bo3bo\$5bo3bo\$6bo3bo\$7bo3bo\$8bo3bo\$9bo3bo\$10bo3bo\$11bo3bo\$12bo3bo\$13bo3bo\$14bo3bo\$15bo3bo\$16bo3bo\$17bo3bo\$18bo3bo\$19bo3bo\$20bo3bo\$21bo2bo\$22b2o!`

Tropylium

Posts: 406
Joined: May 31st, 2011, 7:12 pm
Location: Finland

Tropylium wrote:This pattern makes (two copies of) a traffic light by creating each blinker separately[/code]

DivusIulius

Posts: 89
Joined: April 1st, 2009, 11:23 am

Hey, I have a pile of useless discoveries... Just some examples...

1. Just three silly ways to create LWSSs:

`x = 9, y = 7, rule = B3/S232bo3b2o\$2bo3b2o\$3o3b3o2\$4bo\$4bo\$4bo!`

`x = 5, y = 5, rule = B3/S23obo\$bo2bo\$3o\$bob2o\$ob2o!`

`x = 8, y = 4, rule = B3/S233b4o\$2bo\$bo5bo\$o!`

2. A stupid way to create two closely-spaced gliders...

`x = 7, y = 7, rule = B3/S232o\$obo3bo\$3o2bo\$b4obo\$ob4o\$2o\$2b3obo!`

DivusIulius

Posts: 89
Joined: April 1st, 2009, 11:23 am

I can usually resist this kind of thing, but today I noticed that a kickback reaction into one of Guam's snazzy new 2G-to-G converters produces a fairly clean output glider on the same relative lane, so you get a chain reaction.

So now I wish there was a use for a really really slow one-time kickback reaction that doesn't happen until you've fed in 2^N gliders... but in the meantime, it's a nice Useless Discovery.

`#C N 2G-to-Gs in a spiral absorb 2^N gliders, then kick one backx = 153, y = 173, rule = B3/S23101b2o7b2o\$101b2o7b2o4\$105b2o\$105b2o4\$98bo\$98b3o13b2o\$101bo12b2o\$95b2o3b2o6b2o\$94bobo10bobo\$95bo12bo2\$102b2o11b2o\$95b2o5b2o11b2o\$95b2o2\$92bo\$91bobo18b2o\$91bobo18b2o\$92bo\$97b2o\$96bobo16b2o\$96bo18bobo\$95b2o19b2o4\$129b2o\$128bo2bo\$129b2o\$86b2o50bo\$76b2o7bobo36bo8b2o2bobo\$70b2o4b2o7b2o37b3o6b2o3b2o\$70b2o55bo\$81b2o43b2o13b2o\$81b2o58bo\$59b2o78bobo\$59b2o78b2o10b2o\$72b2o60b2o15b2o\$72bobo59b2o\$73bo\$64b2o80b2o\$64b2o80b2o\$138bo\$76b2o59bobo\$59b2o15b2o60b2o\$59b2o10b2o78b2o\$70bobo78b2o\$70bo58b2o\$69b2o13b2o43b2o\$84bo55b2o\$72b2o3b2o6b3o37b2o7b2o4b2o\$72bobo2b2o8bo36bobo7b2o\$73bo50b2o\$81b2o\$80bo2bo\$81b2o8\$111b2o\$111b2o3\$105b2o\$105b2o5\$92b2o\$91bobo\$93bo11\$79b2o\$78bobo\$80bo11\$66b2o\$65bobo\$67bo11\$53b2o\$52bobo\$54bo11\$40b2o\$39bobo\$41bo11\$27b2o\$26bobo\$28bo11\$14b2o\$13bobo\$15bo11\$b2o\$obo\$2bo!`

I manually placed seeds for a flashy explosion rather than a minimal cleanup, so I'm sure someone can find a solution with the Seeds of Destruction Game using about three blocks. Ah -- I mean, I'm sure nobody will be able to find a clean one- or two-seed solution...!

dvgrn
Moderator

Posts: 5620
Joined: May 17th, 2009, 11:00 pm

dvgrn wrote:I can usually resist this kind of thing, but today I noticed that a kickback reaction into one of Guam's snazzy new 2G-to-G converters produces a fairly clean output glider on the same relative lane, so you get a chain reaction.

OK. Bravo!

DivusIulius

Posts: 89
Joined: April 1st, 2009, 11:23 am

It is well-known that the R-pentomino takes 1103 generations to stabilise. However, adding a blinker in the right location will approximately triple the period whether it is initially in one phase or the other.
`#C R + blinker = 3190 gensx = 24, y = 15, rule = B3/S232o\$b2o\$bo12\$21b3o!`

`#C R + blinker = 3319 gensx = 23, y = 16, rule = B3/S232o\$b2o\$bo11\$22bo\$22bo\$22bo!`
Princess of Science, Parcly Taxel

Freywa

Posts: 518
Joined: June 23rd, 2011, 3:20 am
Location: Singapore

Another useless one: how to arrange two pi-heptominoes so that they produce the maximum population of 2310/2314 cells.

`x = 21, y = 25, rule = B3/S23obo\$obo\$3o20\$18b3o\$18bobo\$18bobo!`

DivusIulius

Posts: 89
Joined: April 1st, 2009, 11:23 am

I think of this one as the "Homer Simpson" reflector.

`x = 22, y = 26, rule = B3/S2310b2o\$10b2o4\$2o\$bo\$bobo11bo\$2b2o10bo\$14b3o6\$4b2o\$4b2o2\$15b2obo\$15b2ob3o\$21bo\$5bob2o6b2ob3o\$3b3obo4bo3bobo\$2bo4bobobobo2bobo\$3b3obob2o2bo3bo\$5b2o6b2o!`
MikeP

Posts: 81
Joined: February 7th, 2010, 9:51 am
Location: Cambridge, UK

MikeP wrote:I think of this one as the "Homer Simpson" reflector.

DivusIulius

Posts: 89
Joined: April 1st, 2009, 11:23 am

A one-time Herschel track:
`x = 100, y = 33, rule = B3/S232bo7b2o\$3o7b2o\$obo\$o\$11bo\$10bobo\$10bobo\$11bo27b2o\$4b2o33b2o\$4bobo\$6bo\$6b2o32bo\$39bobo\$39bobo\$40bo27b2o\$33b2o33b2o\$33bobo\$35bo\$35b2o32bo\$68bobo\$68bobo\$69bo27b2o\$62b2o33b2o\$62bobo\$64bo\$64b2o32bo\$97bobo\$97bobo\$98bo\$91b2o\$91bobo\$93bo\$93b2o!`
hobbyprogrammer77

Posts: 25
Joined: June 12th, 2013, 10:47 am

Four-glider mess takes 22,502 generations to stabilize.

77 gliders and 1 lightweight spaceship are produced...

`x = 17, y = 13, rule = B3/S2385bo\$4bo\$4b3o\$3o\$o\$bo12bobo\$15b2o\$15bo3\$12b3o\$14bo\$13bo!`

I'm not sure if the gliders come from infinity. How might I verify this?

DivusIulius

Posts: 89
Joined: April 1st, 2009, 11:23 am

DivusIulius wrote:I'm not sure if the gliders come from infinity. How might I verify this?

Maybe just use shift.py to move each glider 10 ticks diagonally in the appropriate direction, and see if you still get the same final pattern. In point of fact, you don't:

`x = 15, y = 33, rule = B3/S23813bo\$12bo\$12b3o3\$2bobo\$3b2o\$3bo16\$8b3o\$8bo\$9bo5\$3o\$2bo\$bo!`

So you'd have add a kickback and turn this into a five-glider construction.

I was very surprised to see so many pulsars in the final output, by the way -- until the extra "8" in the rule string caught my eye!

My glider-rewinder script might work, too -- as you step backwards there will come a point when the script refuses to rewind one of the gliders. I've been threatening to get back to write a version that rewinds to N ticks but throws up a warning message if some objects can't be rewound. It wouldn't be terribly difficult, but it seems I haven't found the time yet...!

dvgrn
Moderator

Posts: 5620
Joined: May 17th, 2009, 11:00 pm

These gliders come from infinity though, producing the same result:
`x = 21, y = 12, rule = B3/S238\$9bo\$8bo\$8b3o\$4b3o12bo\$4bo13bo\$5bo12b3o3\$17bo\$16b2o\$16bobo!`
Shannon Omick
skomick

Posts: 73
Joined: February 11th, 2011, 11:41 pm

dvgrn wrote:I was very surprised to see so many pulsars in the final output, by the way -- until the extra "8" in the rule string caught my eye!

Thanks... D'oh! I too noticed the pulsar anomaly but I didn't realize I was pasting a Pulsar Life pattern!

DivusIulius

Posts: 89
Joined: April 1st, 2009, 11:23 am

skomick wrote:These gliders come from infinity though, producing the same result

Thank you very much!

DivusIulius

Posts: 89
Joined: April 1st, 2009, 11:23 am

Another useless one: how to arrange two R-pentominoes so that they produce the maximum population of 2818/2814 cells.
`x = 5, y = 25, rule = B3/S232o\$b2o\$bo20\$3bo\$2b2o\$3b2o!`

Edit: It takes 9,496 generations to stabilize.

DivusIulius

Posts: 89
Joined: April 1st, 2009, 11:23 am

I'm going to spam patterns that produce two somewhat closely-spaced gliders

`x = 4, y = 6, rule = B3/S23b2o\$o2bo\$ob2o\$o\$b2o\$2bo!`

`x = 6, y = 8, rule = B3/S232o\$2o5\$b3o\$3b3o!`

`x = 5, y = 9, rule = B3/S233b2o\$bo2bo\$bo2bo\$bobo4\$2o\$2o!`

`x = 9, y = 5, rule = B3/S232o\$2o3b3o2\$5bo2bo\$6b3o!`

DivusIulius

Posts: 89
Joined: April 1st, 2009, 11:23 am

Unnecessarily expensive beacon:
`x = 38, y = 24, rule = B3/S2334bo2bo\$33bo\$33bo3bo\$33b4o3\$9b2o\$9b3o\$8bob2o\$8b3o\$9bo3\$28bo\$27b3o\$26b2obo\$26b3o\$27b2o3\$b4o\$o3bo\$4bo\$o2bo!`
I Like My Heisenburps! (and others)

Extrementhusiast

Posts: 1752
Joined: June 16th, 2009, 11:24 pm
Location: USA

Old and useless... (Almost)-smallest (in terms of bounding box) patterns (after the glider, r-pentomino and their 3 x 3 predecessors), which produce glider(s).

`x = 5, y = 2, rule = B3/S233b2o\$3obo!`

`x = 5, y = 2, rule = B3/S232bobo\$5o!`

DivusIulius

Posts: 89
Joined: April 1st, 2009, 11:23 am

Another oldie... Smallest (in terms of bounding box) 2-cell thick pattern which produces a LWSS:

`x = 7, y = 2, rule = B3/S232bobobo\$7o!`

DivusIulius

Posts: 89
Joined: April 1st, 2009, 11:23 am

And the smallest (in terms of bounding box) 3-cell thick pattern which produces a LWSS:

`x = 5, y = 3, rule = B3/S23b4o\$b2obo\$2o2bo!`

DivusIulius

Posts: 89
Joined: April 1st, 2009, 11:23 am

And finally, the smallest (in terms of bounding box) 4-cell thick pattern which produces a LWSS:

`x = 4, y = 4, rule = B3/S23b3o\$3bo\$2b2o\$3o!`

DivusIulius

Posts: 89
Joined: April 1st, 2009, 11:23 am

Three-glider mess takes 8,140 generations to stabilize. 26 gliders are produced...

`x = 13, y = 12, rule = B3/S23obo\$b2o\$bo3\$12bo\$10b2o\$11b2o2\$8bo\$8b2o\$7bobo!`

Three-glider mess takes 10,772 generations to stabilize. 20 gliders are produced...
`x = 21, y = 30, rule = B3/S2320bo\$18b2o\$19b2o23\$2bo\$obo\$b2o2bo\$5bobo\$5b2o!`

DivusIulius

Posts: 89
Joined: April 1st, 2009, 11:23 am

`#C Pi + R = 5548 generations to stabilisex = 21, y = 23, rule = B3/S23o\$bo\$bo\$2o17\$19b2o\$18b2o\$19bo!`
Princess of Science, Parcly Taxel

Freywa

Posts: 518
Joined: June 23rd, 2011, 3:20 am
Location: Singapore

Next