Extrementhusiast wrote:16.723 and 16.833 in at most eleven gliders each:
16.723 in 10 gliders (may be further reducible by using 2 constellations):
Code: Select all
x = 116, y = 38, rule = B3/S23
bo$2bo$3o8$49b2o28b2o30b2o$49b2o28b2o30bobo$39bo48bo24bo$39bobo44b2o
25b2o$39b2o46b2o22b2o2bo$37bo72bo2bobo$17bo17bobo29b2o28b2o11b2o2bo$
15bobo18b2o12bo15bo2bo10bo15bo2bo$16b2o2bo28bobo15b2o10bobo15b2o2b2o$
20bobo26bobo27bobo19bobo$20b2o28bo29bo20bo2$18bo$19b2o$18b2o35bo29bo$
55bo29bo$55bo29bo8$3b3o$5bo100b3o$4bo101bo$107bo!
16.833 in 11 gliders (could not find a 3G synthesis of the blinker constellation):
Code: Select all
x = 34, y = 25, rule = B3/S23
23bo$15bo5b2o$16bo5b2o$10bo3b3o$obo8bo$b2o6b3o$bo3$2o$b2o$o2$5bo$6b2o
5b2o$5b2o6bobo$13bo2$6bo$6b2o2b3o$5bobo4bo$11bo2b3o$14bo16b3o$15bo15bo
$32bo!
Extrementhusiast wrote:
The first soup for the latter even suggests a component:
Code: Select all
x = 19, y = 17, rule = B3/S23
2b2o$bobo$bo12bo$2o11bobo$2b2o8bo2bo$2bobo8b2o$3bo3$15b3o$18bo$18bo$
15b3o2$12b3o2$12bo!
It reduces to this:
Code: Select all
x = 33, y = 27, rule = B3/S23
2b2o18b2o$bobo2b2o13bobo2b2o$bo3b2o14bo4bo3bo$2o18b2o4bo3bobo$2b2o3bob
o12b2o6b2o$2bobo2b2o13bobo2b2o$3bo3b2o14bo3b2o14$2b2o18b2o$bobo2b2o13b
obo2b2o$bo3b2o14bo3b2o$2o18b2o$2b2o3bo14b2o3bobo$2bobo2b2o13bobo2b3o$
3bo3b3o13bo3b2o!
EDIT:
Extrementhusiast wrote:EDIT: 16.18 in nine gliders:
Code: Select all
x = 47, y = 49, rule = B3/S23
o$b2o$2o13$22bo$20b2o$16bobo2b2o$17b2o$17bo3$25bo$20bo4bo$18bobo4bo$
19b2o4$15b2o$14bobo$16bo4$28b2o$27b2o$29bo9$45b2o$44b2o$46bo!
Reduced to 8 gliders:
Code: Select all
x = 47, y = 49, rule = B3/S23
o$b2o$2o13$22bo$20b2o$16bobo2b2o$17b2o12bo$17bo11b2o$30b2o3$20bo$18bob
o$19b2o6b2o$27bobo$27bo8$28b2o$27b2o$29bo9$45b2o$44b2o$46bo!
EDIT2:
16.1740 in 9 gliders:
Code: Select all
x = 38, y = 51, rule = B3/S23
13bo$11bobo$12b2o5$18bo$16bobo$17b2o2$28bo$26bobo$27b2o2$23bo5bo$13b2o
6bobo5bobo$12bobo7b2o5b2o$14bo6$17b2o$16bobo$18bo16b3o$35bo$36bo20$2o$
b2o$o!
Can anyone make a converter out of this?:
Code: Select all
x = 12, y = 17, rule = B3/S23
8b2o$10b2o$5bob2o$3bobobo$4b2obobo$8bobo$9bo2$2bo$obo$b2o$4bo$3bobob2o
$3bobobo$4b2obobo$8bobo$9bo!
EDIT3:
Here's a synthesis of 16.1846 that is probably cheaper than whatever the above possible converter might give.
16.1846 in 11 gliders:
Code: Select all
x = 24, y = 24, rule = B3/S23
23bo$8bo12b2o$6bobo13b2o$7b2o2$19bobo$8bo10b2o$6bobo11bo$7b2o2bo$10bo$
10b3o4bobo$17b2o$11bo6bo$10b2o$10bobo$2bo$obo$b2o2$3b3o$5bo3b2o$4bo5b
2o6bo$9bo7b2o$17bobo!
It uses this new converter:
Code: Select all
x = 24, y = 24, rule = B3/S23
23bo$8bo12b2o$6bobo13b2o$7b2o2$19bobo$3b2o14b2o$3bobo14bo$4bobo$5bobo$
6bobo8bobo$7bobo7b2o$8bobo7bo$9bo2$2bo$obo$b2o2$3b3o$5bo3b2o$4bo5b2o6b
o$9bo7b2o$17bobo!