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The Hunting of the New Herschel Conduits

For discussion of specific patterns or specific families of patterns, both newly-discovered and well-known.

Re: The Hunting of the New Herschel Conduits

Postby BlinkerSpawn » October 1st, 2017, 5:08 pm

Kazyan wrote:I found some better stabilizations from the search, but nothing completely clean. The yellow eater in this version suppresses a bit of junk that looks like it'd be easy to make clean, but has been so resilient to cleanup that both CatForce (2 catalysts) and Bellman (max-active 9) haven't come up with a clean version. Not that it matters much, since the R output seems too finicky to use, per Jormungant.

rle

Trivially combining your and Jurmongant's suggestions solves the hive:
x = 31, y = 46, rule = LifeHistory
7.2A$7.A$8.3A$10.A3.2A$14.2A8.2A$24.A$6.2A14.A.A$7.A14.2A$7.A.A$8.2A
19.2E$29.E$27.E.E$27.2E$2A$.A$.A.A$2.2A7$2.C$2.C.C$2.3C22.A$4.C21.A.A
$26.A2.A$24.3A3.A$23.A3.3A$6.12B5.4A$5.D12B9.A$4.2D13B4.2A.2A$3.2D11B
2DB4.A4.2A$4.D10B2D2B5.2A.A2.A$5.D10BD2B6.A.A.A$8.11B6.A2.A$9.2B.7B7.
2A$13.4B$15.3B$14.B2A3B$15.A2.A.A$16.3A.3A$19.A3.A$16.2A.A2.2A$16.A.A
!

Of course, there's still the B's annoying block.
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Re: The Hunting of the New Herschel Conduits

Postby A for awesome » October 1st, 2017, 5:18 pm

Kazyan wrote:I found some better stabilizations from the search, but nothing completely clean. The yellow eater in this version suppresses a bit of junk that looks like it'd be easy to make clean, but has been so resilient to cleanup that both CatForce (2 catalysts) and Bellman (max-active 9) haven't come up with a clean version. Not that it matters much, since the R output seems too finicky to use, per Jormungant.

x = 31, y = 38, rule = LifeHistory
7.2A$7.A$8.3A$10.A3.2A$14.2A8.2A$24.A$6.2A14.A.A$7.A14.2A$7.A.A$8.2A
19.2E$29.E$27.E.E$27.2E$2A$.A$.A.A$2.2A7$2.C$2.C.C$2.3C22.A$4.C21.A.A
$26.A2.A$24.3A3.A$23.A3.3A$23.4A$27.A$23.2A.2A$23.A4.2A$24.2A.A2.A$
25.A.A.A$25.A2.A$26.2A!

Well, here's a dependent H-B that probably has no input or output:
x = 32, y = 46, rule = LifeHistory
7.2A$7.A$8.3A$10.A3.2A$14.2A8.2A$24.A$6.2A14.A.A$7.A14.2A5.A$7.A.A17.
3A$8.2A16.A$26.2A3$2A$.A$.A.A$2.2A24.2A$28.A.A$30.A$30.2A4$2.C$2.C.C$
2.3C22.A$4.C21.A.A$26.A2.A$24.3A3.A$23.A3.3A$23.4A$27.A$23.2A.2A$23.A
4.2A$24.2A.A2.A$25.A.A.A$25.A2.A$26.2A3$15.2A$15.A2.A.A$16.3A.3A$19.A
3.A$16.2A.A2.2A$16.A.A!
x₁=ηx
V ⃰_η=c²√(Λη)
K=(Λu²)/2
Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt)

$$x_1=\eta x$$
$$V^*_\eta=c^2\sqrt{\Lambda\eta}$$
$$K=\frac{\Lambda u^2}2$$
$$P_a=1-\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$

http://conwaylife.com/wiki/A_for_all

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Re: The Hunting of the New Herschel Conduits

Postby calcyman » October 2nd, 2017, 4:03 am

A for awesome wrote:Well, here's a dependent H-B that probably has no input or output:


It definitely has a usable output; the input might be slightly more difficult:

x = 63, y = 72, rule = LifeHistory
38.2A$38.A$39.3A2.2B$41.A3B2A$43.2B2A2B6.2A$43.6B6.A$37.2A3.7B3.BA.A$
38.A4.6B3.B2A5.A$38.A.AB.10B5.3A$39.2AB.10B4.A$41.12B4.2A$41.18B$41.
16B$31.2A8.18B$32.A9.17B$32.A.AB4.19B$33.2AB.20B.B2A$35.21B2.BA.A$35.
20B6.A$36.19B6.2A$35.20B$33.22B$31.24B$31.2BC22B$30.3BCBC20B$31.2B3C
4B.13B4.A$12.2A16.5BC4B2.12B3.A.A$12.A2.A13.10B2.9B.2B4.A2.A$13.3A12.
8B5.11B3.3A3.A$7.2A18.8B4.15BAB2.3A$7.A.A5.3A8.8B.19B4A$2.A6.A4.A2.AB
4.13BD17B.B2.A$2.3A4.2A3.2A2B4.13B2D17B2AB2A$5.A4.B4.B.3B2.12B2D15B3.
AB3.2A$4.2A4.2B2.7B.13BD15B4.2A.A2.A$4.10B.21BD14B5.A.A.A$6.30B3.11B
6.A2.A$5.24B2.4B5.2B.7B7.2A$5.22B3.4B10.4B$6.20B3.4B13.3B$7.20B.4B13.
B2A3B$7.24B15.A2.A.A$10.20B17.3A.3A$9.20B21.A3.A$9.19B19.2A.A2.2A$8.
19B20.A.A$4.17B.4B$3.2A15B.4B$3.2A19B$4.19B$6.16B$5.16B$4.4B.11B$4.3B
.11B$2.2AB3.10B$.A.AB3.9B$.A5.10B2.B$2A3.B.10B.B2A$4.2A13B2A$4.2A11B.
2B$5.12B$5.3B.9B$8.11B$8.12B$9.7B.4B$10.7B.4B$8.B.19B$7.2A3B2A11BD4B$
7.2AB.B2A9B3D4B$8.B2.12BDBD4B$12.11BD6B$13.B2.2B2.10B!


EDIT: This might be a potential route of attack, if the white object can be inserted:

x = 63, y = 72, rule = LifeHistory
38.2A$38.A$39.3A2.2B$41.A3B2A$43.2B2A2B6.2A$43.6B6.A$37.2A3.7B3.BA.A$
38.A4.6B3.B2A5.A$38.A.AB.10B5.3A$39.2AB.10B4.A$41.12B4.2A$41.18B$26.C
14.16B$24.BCB4.2A8.18B$22.3BCB5.A9.17B$20.5BC6.A.AB4.19B$20.3BCB3C5.
2AB.20B.B2A$20.3BC2BCB7.21B2.BA.A$21.2B3C3B6.20B6.A$20.9B7.19B6.2A$
20.8B7.20B$20.8B5.22B$18.10B2.25B$17.16BD22B$16.7B2A8BDBD20B$16.6BABA
8B3D4B.13B4.A$17.5B2A11BD4B2.12B3.A.A$13.2A4.20B2.9B.2B4.A2.A$12.A2.A
5.6B.8B5.11B3.3A3.A$7.2A3.3A12.8B4.15BAB2.3A$7.A.A5.3A8.8B.19B4A$2.A
6.A4.A2.AB4.13BD17B.B2.A$2.3A4.2A3.2A2B4.13B2D17B2AB2A$5.A4.B4.B.3B2.
12B2D15B3.AB3.2A$4.2A4.2B2.7B.13BD15B4.2A.A2.A$4.10B.21BD14B5.A.A.A$
6.30B3.11B6.A2.A$5.24B2.4B5.2B.7B7.2A$5.22B3.4B10.4B$6.20B3.4B13.3B$
7.20B.4B13.B2A3B$7.24B15.A2.A.A$10.20B17.3A.3A$9.20B21.A3.A$9.19B19.
2A.A2.2A$8.19B20.A.A$4.17B.4B$3.2A15B.4B$3.2A19B$4.19B$6.16B$5.16B$4.
4B.11B$4.3B.11B$2.2AB3.10B$.A.AB3.9B$.A5.10B2.B$2A3.B.10B.B2A$4.2A13B
2A$4.2A11B.2B$5.12B$5.3B.9B$8.11B$8.12B$9.7B.4B$10.7B.4B$8.B.19B$7.2A
3B2A11BD4B$7.2AB.B2A9B3D4B$8.B2.12BDBD4B$12.11BD6B$13.B2.2B2.10B!
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Re: The Hunting of the New Herschel Conduits

Postby Jormungant » October 2nd, 2017, 4:02 pm

There is also the possibility of starting with a B instead of a H, that new B-to-H block gets removed with the current construction:

x = 58, y = 64, rule = LifeHistory
13$29.2A$29.A$30.3A2.2B$32.A3B2A$34.2B2A2B6.2A$34.6B6.A$28.2A3.7B3.BA
.A$29.A4.6B3.B2A5.A$29.A.AB.10B5.3A$30.2AB.10B4.A$32.12B4.2A$32.18B$
32.16B$32.18B$33.17B$31.19B$28.20B.B2A$27.20B2.BA.A$26.20B6.A$27.19B
6.2A$14.5B7.20B$14.5B5.22B$14.5B2.25B$14.33B$14.2B2C29B$14.3B2C12B.
13B4.A$14.2B2C13B2.12B3.A.A$14.2BC13B2.9B.2B4.A2.A$14.4B.8B5.11B3.3A
3.A$18.8B4.15BAB2.3A$17.8B.19B4A$14.13BD17B.B2.A$14.12B2D17B2AB2A$14.
11B2D15B3.AB3.2A$14.12B2D14B4.2A.A2.A$14.13B.14B5.A.A.A$14.13B3.11B6.
A2.A$31.2B.7B7.2A$35.4B$37.3B$36.B2A3B$37.A2.A.A$38.3A.3A$41.A3.A$38.
2A.A2.2A$38.A.A!
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Re: The Hunting of the New Herschel Conduits

Postby A for awesome » November 5th, 2017, 11:25 am

Is there any way to restore the upper block or replace it with an equivalent catalyst?
x = 28, y = 21, rule = LifeHistory
6.A9.A$6.3A5.3A$9.A3.A11.3D$8.2A3.2A10.D.D$24.D2.D$24.2D$10.2C$10.2C
9$21.C$2.2A11.2C3.3C$.A.A11.2C2.2C.C$.A$2A!

(Or bolt on an incomplete C-X that happens to put junk in the right place to delete the irritating mess that destroys the lower block and the eater.)
x₁=ηx
V ⃰_η=c²√(Λη)
K=(Λu²)/2
Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt)

$$x_1=\eta x$$
$$V^*_\eta=c^2\sqrt{\Lambda\eta}$$
$$K=\frac{\Lambda u^2}2$$
$$P_a=1-\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$

http://conwaylife.com/wiki/A_for_all

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