How about a dart synthesis?

[simsim314]

Here is a recipe with debris (40 gliders - 4 for 2pi):

Code: Select all

x = 257, y = 227, rule = B3/S23
10bo$11bo$9b3o3$11bo8bo$12bo5bobo$10b3o6b2o$4bobo$5b2o206bo$5bo200bobo
3bo$206b2o4b3o5bo$207bo11bo$219b3o$225bo$223b2o$224b2o$12bo$3bobo7bo$
4b2o5b3o3bo189bo$4bo13b2o185b2o$17b2o187b2o29$251bo$249b2o$250b2o4$58b
obo$59b2o$59bo109$62bo$62b2o$61bobo$165b3o$165bo$166bo$172bo$171b2o$
171bobo6$62b2o$63b2o$62bo6$254b2o$254bobo$254bo3$117b3o$119bo$118bo9$
8b3o$10bo3b2o$9bo3bobo$15bo43bo$59b2o$58bobo3$48bo130b2o35b3o$35bo12b
2o128b2o36bo$5bo29b2o10bobo130bo36bo$5b2o27bobo184bo$4bobo213b2o$220bo
bo2$3o$2bo227b2o$bo228bobo$230bo$225b2o$224b2o$226bo!

I think we should improve the right wing spark synth, and debris from that one can clean some of the 2pi.

There is also this 5 gliders recipe (see generation 96):

Code: Select all

x = 45, y = 34, rule = B3/S23
2bo10bobo$obo11b2o$b2o11bo2$42bobo$42b2o$18bo24bo$16bobo$17b2o$31bo$
29b2o$30b2o19$22b2ob2o$23bobo$22bo3bo$22b2ob2o!
 

And this 6 gliders (that might be reduced):

Code: Select all

x = 30, y = 14, rule = B3/S23
28bo$27bo$14bo12b3o$2bo10bo$obo10b3o$b2o4$6bobo16bo$7b2o14b2o$7bo8bo7b
2o$16bobo$16b2o!

[chris_c]

The following two glider collision yields a hive predecessor at the southern tip after 16 generations:

Code: Select all

x = 9, y = 7, rule = B3/S23
obo$b2o$bo2$8bo$6b2o$7b2o!

Based on tweaks to that reaction I found a couple of frustratingly near misses (see generation 18):

Code: Select all

x = 73, y = 12, rule = B3/S23
7bo$o7bo2bobo36bo6bo3bobo6bobo$b2o3b3o3b2o37b2o2bobo4b2o6b2o$2o10bo37b
2o4b2o4bo8bo2$19bo49bo$17b2o48b2o$18b2o48b2o$5bo49bo$5b3o47b3o$8bob2o
46bob2o$7b2ob2o45b2ob2o!

I wonder if anyone can get this to work properly. If successful it should allow the wings to be symmetrical again.

[simsim314]

I wonder if anyone can get this to work properly. If successful it should allow the wings to be symmetrical again.

Here it is!

Code: Select all

x = 35, y = 38, rule = B3/S23
26bo$24b2o$25b2o2$2bobo$3b2o10bo3bo8bo$3bo3bobo3bobo4b2o4b2o$8b2o4b2o
3b2o6b2o$8bo2$24bobo$24b2o$12bo12bo$12b3o$15bob2o$5bo8b2ob2o10bo$3bobo
23bobo$4b2o23b2o$15b2ob2o$15bo3bo$5b2o9bobo9b2o$4bobo8b2ob2o8bobo$6bo
21bo2$bo15bo15bo$b2o13bobo13b2o$obo14bo14bobo2$9b2o13b2o$10b2o11b2o$9b
o15bo$18b2o$18bobo$18bo2$16b2o$15bobo$17bo!

EDIT

Here is 6 gliders back

Code: Select all

x = 177, y = 135, rule = B3/S23
13$127bobo$127b2o$128bo$52bo$53b2o9bo$52b2o3bo7bo2bobo58bobo$58b2o3b3o
3b2o58b2o$57b2o10bo60bo2$128bo$126b2o$127b2o3$54bo77bo$55bo75bo$53b3o
75b3o22$88bo$88b3o$91bob2o$90b2ob2o3$91b2ob2o$91bo3bo$92bobo$91b2ob2o
22$76b2o23bo$75bobo22b2o$77bo22bobo2$54b3o73b3o$56bo73bo$55bo75bo$110b
2o$50b2o25b2o30b2o24b2o$51b2o23bobo25b3o4bo22b2o$50bo27bo25bo31bo$105b
o8$134bo$133b2o$133bobo!

---

And in total:

6 (wings) + 3 (block + eater ?) + 7 (top ignition) + 5 (core snake pair) + 6 (back) = 27

Can someone place "block + eater" there with 3 (or 4) gliders?

[chris_c]

Here it is!

Great! Looks like I gave up without realising how close I was. Didn't have the patience to add a 5th glider. Congrats.

(EDIT: looking at it again you have combined the ideas of my first two patterns and added a 5th glider to clean up. Nicely done! )

6 (wings) + 3 (block + eater ?) + 7 (top ignition) + 5 (core snake pair) + 6 (back) = 27

I just used the eater because it was easier to draw and trivial to clean up the junk loaf. There is this recipe costing 8 gliders or we can go back to the integral sign method costing 7. I originally hoped that the eater + block would be "easy" to make but haven't been able to prove that so far.

[simsim314]

looking at it again you have combined the ideas of my first two patterns and added a 5th glider to clean up.

Yep...

here is this recipe costing 8 gliders or we can go back to the integral sign method costing 7

This is simple and common spark, that placed two cells above the core, it shouldn't cost so much. It's probably possible to convert block into it with 3-4 gliders, or find a way to place block with eater on that spot with 3-4 gliders.

EDIT Looking at it again I might be over-optimistic, but this feels a bit of a waste there. Otherwise everything else looks pretty tight. The other spark is optimized well, the wings are best, the back might be improved by 1 but not very probably, the other part of the front spark is also very tight. Everything looks at their almost best except this 7 gliders for so simple spark.

EDIT2 Maybe something like this could work:

Code: Select all

x = 6, y = 9, rule = B3/S23
2o$2o$4b2o$2ob2o$5bo$b3o2$obo!

EDIT3 Here is something that looks promising:

Code: Select all

x = 7, y = 7, rule = B3/S23
4bo$2o2bo$obobo$3o$5bo$4bobo$5b2o!

[simsim314]

Here it's all placed together.

Code: Select all

x = 287, y = 295, rule = B3/S23
7bo$8bo$6b3o2$277bobo$277b2o$278bo$8bo$9bo4bo$7b3o5bo2bobo258bobo$13b
3o3b2o258b2o$19bo260bo2$278bo$276b2o$277b2o3$4bo277bo$5bo275bo$3b3o
275b3o15$42bo$43bo$41b3o191bo$235bobo$235b2o2$34bo$32bobo$33b2o34$201b
o$199b2o$200b2o7$82bo$80bobo$81b2o32$122bo$123b2o$122b2o43$125b2o$126b
2o$125bo36b2o$162bobo$162bo2$168b2o$167b2o$169bo5$126bo$126b2o$125bobo
19$83bo$83b2o$82bobo29$39bo$39b2o$38bobo41$26b2o223bo$25bobo222b2o$27b
o222bobo2$4b3o273b3o$6bo273bo$5bo275bo$260b2o$2o25b2o230b2o24b2o$b2o
23bobo225b3o4bo22b2o$o27bo225bo31bo$255bo8$284bo$283b2o$283bobo!

Unfortunately couldn't come up with something better for the left spark, so it takes 7 for preparation and 2 for ignition, so in total we stand now on 31. Here is BOM for the synth:

Core (snake pair) - 5 optimized (probably best)
Wings - 6 (best)
Spark preset - 7 (probably can be improved)
Right spark - 5 (well optimized).
Left spark - 2 (maybe with other preset could be improved)
Back spark - 6 (optimized)
------
Total: 31

[codeholic]

If I'm not mistaken, the repeat time for this synthesis is 293, which is a prime number

Code: Select all

x = 271, y = 278, rule = B3/S23
8bo$6bobo$7b2o$262bo$260b2o$261b2o2$9bo$7bobo5bo3bo244bo$8b2o3bobo4b2o
240b2o$14b2o3b2o242b2o3$260bobo$260b2o$261bo3$5bo259bo$3bobo259bobo$4b
2o259b2o7$34bo$35b2o$34b2o190bobo$226b2o$227bo2$25bobo$26b2o$26bo8$
218bo$216b2o$217b2o7$49bo$47bobo$48b2o8bo$59bo$57b3o17$80bo$81b2o$80b
2o$188bo$187bo$187b3o2$81bo$82b2o3bo5bo96bo$81b2o5b2o4bo94bo$87b2o3b3o
94b3o3$187bo$187bobo$187b2o3$77bo115bo$78b2o111b2o$77b2o113b2o7$108bo$
109bo$107b3o43bo$153bobo$153b2o2$100bo$98bobo$99b2o8$144bo$143bo$143b
3o7$121bo$122b2o$121b2o$130bobo$131b2o$131bo9$134bo$134b2o$133bobo$
123b2o12b3o$122bobo12bo$124bo13bo$144bo$143b2o$105bo37bobo$105b2o$104b
obo4$134b2o$135b2o$134bo27$100bo$100b2o58b3o$99bobo58bo$161bo$78b2o
111b2o$79b2o109b2o$78bo113bo$170b2o$74b2o25bo68bobo22b2o$73bobo25b2o
62b2o3bo24bobo$75bo24bobo61b2o29bo$166bo9$193b3o$193bo$194bo9$60b3o$
62bo$50bo10bo149b2o$50b2o158b2o$49bobo160bo2$216b3o$216bo$31b3o183bo$
33bo$32bo3$61b2o$60bobo$62bo28$26b3o205b2o$28bo204b2o$27bo207bo$5b2o
257b2o$4bobo257bobo$6bo257bo$244bo$bo241b2o24bo$b2o24b3o208b2o3bobo22b
2o$obo26bo208bobo27bobo$28bo209bo9$267b2o$266b2o$268bo!

[dvgrn]

If I'm not mistaken, the repeat time for this synthesis is 293, which is a prime number :roll

No, no -- it's 289, which is the next higher square-of-a-prime-number than the previous repeat rate of 169:

Code: Select all

x = 269, y = 276, rule = B3/S23
6bobo$7b2o$7bo$259bo$259bobo$259b2o2$7bobo$8b2o3bobo4bo240bo$8bo5b2o2b
obo240bobo$14bo4b2o240b2o2$259bo$258bo$258b3o4$3bobo257bobo$4b2o257b2o
$4bo259bo7$35bo$33bobo189bo$34b2o188bo$224b3o2$26bo$27bo$25b3o9$215bo$
215bobo$215b2o7$47bobo$48b2o$48bo8bo$58b2o$57b2o16$80bo$78bobo$79b2o$
188bo$186b2o$187b2o2$81bo$79bobo5bo3bo98bo$80b2o3bobo4b2o94b2o$86b2o3b
2o96b2o3$186bobo$186b2o$187bo3$77bo113bo$75bobo113bobo$76b2o113b2o7$
106bo$107b2o$106b2o44bobo$152b2o$153bo2$97bobo$98b2o$98bo8$144bo$142b
2o$143b2o7$121bo$119bobo$120b2o8bo$131bo$129b3o11$132b3o$134bo$122bo
10bo3b2o$122b2o12b2o$121bobo14bo2$142b3o$142bo$103b3o37bo$105bo$104bo
3$133b2o$132bobo$134bo28$98b3o59b2o$100bo58b2o$99bo61bo$77b2o111b2o$
76bobo111bobo$78bo111bo$170bo$73bo95b2o24bo$73b2o24b3o62b2o3bobo22b2o$
72bobo26bo62bobo27bobo$100bo63bo9$193b2o$192b2o$194bo8$60b2o$61b2o$60b
o148b2o$49b3o157bobo$51bo157bo$50bo$215b2o$214b2o$31b2o183bo$32b2o$31b
o3$61bo$61b2o$60bobo28$26b2o204b2o$27b2o203bobo$26bo205bo$5bo257bo$5b
2o255b2o$4bobo255bobo2$241b3o$3o24b2o208bo3bo24b3o$2bo25b2o206b2o4bo
23bo$bo25bo208bobo28bo9$265b2o$265bobo$265bo!

[chris_c]

Unfortunately couldn't come up with something better for the left spark

Me neither. I did have a play around with apgsearch to try to find natural synthesis of block-on-eater, but nothing concrete so far.

There were about 20 occurences of block-on-eater in 2,000,000 soups. The majority were variants of this:

Code: Select all

x = 14, y = 16, rule = B3/S23
12b2o$12b2o$3bobo$3bobo$3b3o7$3o2$4bo$4bo$4bo!

but they don't look suitable because the blinker is one cell too far south and would interact with the snake.

Most other occurences were fairly wild but there was this one:

Code: Select all

x = 16, y = 16, rule = B3/S23
4bobo3b3obo$bob4ob4obo$o2bobob2o4bobo$b3ob2o3bobob2o$2obobob4o3bo$2b2o
3bobobob2o$2o2b4obobob3o$obo2bo3bobo2bo$b5obobo2b2o$3obob2o2b6o$2ob2ob
3ob6o$3o5b2o2b2o$2obob4ob3o2bo$ob3obobob2o$2o3b3obo4bo$2b3obob4obo!

that hints at the following synthesis:

Code: Select all

x = 20, y = 13, rule = B3/S23
bo$2bo14bo$3o14bobo$14bo2b2o$8b2o5bo$7bo2bo2b3o$6b2o2bo$7b2obo$8bo$9bo
2b2ob2o$12bo3bo$13bobo$12b2ob2o!

Also I found that block-on-eater is easily obtained from block-on-beacon:

Code: Select all

x = 7, y = 13, rule = B3/S23
5bo$4bo$4b3o2$o$b2o$2o3$2o$2o$2b2ob2o$2b2ob2o!

and that block-on-beacon is _very_ common. Almost as common as MWSS. Unfortunately _every_ soup I looked at (maybe 50 of them) contained this predecessor:

Code: Select all

x = 6, y = 5, rule = B3/S23
o$3o$3o2$3b3o!

which is not suitable for the same reason as the pi + 2 blinker pattern above.

I found a single instance of block-on-intergral-sign but it was completely wild.

The initialisation of my decompositions dictionary in apgsearch reads:

Code: Select all

decompositions = {"xs18_3pq3qp3": ["xs14_3123qp3", "xs4_33"],
                      "xs11_0gbrz23": ["xs11_0gbrz23"],
                      "xp2_rbzw23": ["xp2_rbzw23"],
                      "xs13_330354ko": ["xs13_330354ko"]}

and I added these to the commonnames dictionary:

Code: Select all

                   "xs11_0gbrz23": ("block-on-eater", 50),
                   "xp2_rbzw23": ("block-on-beacon", 40),
                   "xs13_330354ko": ("block-on-integral-sign", 60)}

if anyone wants to try their luck.

[Kazyan]

Maybe 6 gliders from this LoM predecessor + honey farm predecessor:

Code: Select all

x = 7, y = 5, rule = B3/S23
2o$2o2b3o$2bo3bo$b2obo$5bo!

Getting the LoM predecessor there is proving to be very finicky with the relevant 2-glider synthesis for the other half, though. I'll see what else comes up.

[simsim314]

Here are some variations on the left spark:

Code: Select all

x = 300, y = 42, rule = B3/S23
20$145bo51bo58b2o$27b2o59bo58b2o49bo57b3o$27b2o6bo51b2o6bo49bob2o6bo
39bob2o6bo52bo6bo$28bobo4bo51b2obo4bo49bob2obo4bo39bob2obo4bo49bob2obo
4bo$31b4o56b4o56b4o46b4o56b4o$21b2o15b2o41b2o15b2o41b2o15b2o31b2o15b2o
41b2o15b2o$20b4o4b2ob2o4b4o39b4o4b2ob2o4b4o39b4o4b2ob2o4b4o29b4o4b2ob
2o4b4o39b4o4b2ob2o4b4o$19bo2bobo3bo3bo3bobo2bo37bo2bobo3bo3bo3bobo2bo
37bo2bobo3bo3bo3bobo2bo27bo2bobo3bo3bo3bobo2bo37bo2bobo3bo3bo3bobo2bo$
18b3o2b3o3bobo3b3o2b3o35b3o2b3o3bobo3b3o2b3o35b3o2b3o3bobo3b3o2b3o25b
3o2b3o3bobo3b3o2b3o35b3o2b3o3bobo3b3o2b3o$19bo3b2o3b2ob2o3b2o3bo37bo3b
2o3b2ob2o3b2o3bo37bo3b2o3b2ob2o3b2o3bo27bo3b2o3b2ob2o3b2o3bo37bo3b2o3b
2ob2o3b2o3bo$20b4o4bo3bo4b4o39b4o4bo3bo4b4o39b4o4bo3bo4b4o29b4o4bo3bo
4b4o39b4o4bo3bo4b4o$21b2o6bobo6b2o41b2o6bobo6b2o41b2o6bobo6b2o31b2o6bo
bo6b2o41b2o6bobo6b2o$28bo3bo55bo3bo55bo3bo45bo3bo55bo3bo!

[simsim314]

There are many potential ways that could ignite the block directly as well:

Code: Select all

x = 136, y = 14, rule = B3/S23
4bo27b2o$b2o100bo$ob3o3b2o23bobo3b2o14bobo44b2o22b2o$8b3o28b3o13bobo
20bob2o3b2o15b3o3b2o$4b2ob6o22b2ob6o11bobo3b2o22b3o20b3o14bobo3b2o$4b
2ob6o22b2ob6o17b3o14bo2b2ob6o14b2ob6o18b3o$57b2ob6o15b2ob6o14b2ob6o14b
2ob6o$57b2ob6o61b2ob6o$5b2ob2o26b2ob2o$5bo3bo26bo3bo41b2ob2o18b2ob2o$
6bobo28bobo18b2ob2o19bo3bo18bo3bo18b2ob2o$5b2ob2o26b2ob2o17bo3bo20bobo
20bobo19bo3bo$59bobo20b2ob2o18b2ob2o19bobo$58b2ob2o65b2ob2o!

Those simple sparks should be possible to produce with 3-4 gliders, or SL + 1-2 G.

[Extrementhusiast]

p300 edgeshooter:

Code: Select all

x = 96, y = 72, rule = LifeHistory
63.2A$64.A$64.A.A$65.2A6$64.2A$64.2A4.2A$70.2A4$69.2A$65.2A2.2A$64.A.
A$64.A12.2A4.3C$63.2A11.A.A5.C$76.A7.3C$75.2A4$53.2A$37.2A15.A22.2A$
37.A.A14.A.A19.A.A$32.2A4.3A7.2A5.A.A8.A9.A$28.4A2.A4.3A6.2A6.A3.2A4.
3A5.3A$28.3A.2A4.3A19.2A7.A3.A$37.A.A28.2A3.2A$37.2A2$61.D$34.2A23.3D
$34.A12.2A10.D.D23.2A$26.A5.A.A12.2A10.D25.2A7.2A$25.2A5.2A60.A$3.A5.
2A13.2A11.2A53.A.A$.A3.A3.3A11.3A11.2A53.2A$5.A5.2A.A9.2A3.2A$A5.A4.A
2.A10.2A26.2A$2A9.2A.A11.A26.A.A$9.3A10.A32.A$9.2A9.A.A32.2A31.2A$21.
2A65.A.A$90.A$51.2A9.2A26.2A$51.A.A9.A$53.A6.3A3.A.2A$53.2A5.A2.4A.2A
$63.A$64.3A.2A$33.2A31.2A2.A$32.A.A34.2A$34.A4$41.2A$41.A.A$25.3A15.A
$14.A12.A15.2A$14.4A8.A$4.2A9.4A10.2A$4.2A9.A2.A9.A.A$9.A5.4A8.3A4.2A
.3A$9.A4.4A8.3A4.A2.4A$14.A12.3A4.2A$28.A.A$29.2A!

[chris_c]

Boat and block can be ignited by B-heptomino. Please, please someone find a good synthesis for this!

Code: Select all

x = 31, y = 35, rule = B3/S23
22bo$20b2o$21b2o3$15bo3bo4bo$7bo5bobo4b4o$7b2o5b2o3b2o2b2o$8b2o10bo$7b
2o$20bobo$12bo7b2o$11bobob2o4bo$12b2ob2o2$3b2o21b2o$2b2obo7b2ob2o7bob
2o$b2o2b2o6bo3bo6b2o2b2o$2b2o2bo7bobo7bo2b2o$3b4o6b2ob2o6b4o$b5o19b5o$
b2o25b2o$obo12bo12bobo$14bobo$9b2o4bo4b2o$10b2o7b2o$9bo11bo$15bo$14b3o
$13bo2bo3$15bo$16bo$15bo!

[simsim314]

Boat and block can be ignited by B-heptomino.

Great! unfortunately the space there is very limited, it's kinda hard.

p300 edgeshooter

I've gone back and forth there 10 times by now, I can't find anything relevant There are many small sparks, but nothing that clicks (for me at least).

[chris_c]

Here we go:

Code: Select all

x = 39, y = 42, rule = B3/S23
30bo$28b2o$29b2o$7bo$8b2o$7b2o6bo3bo12bo$13bobo4b2o8b2o$14b2o3b2o10b2o
2$9bo$10bo17bobo$8b3o17b2o$29bo2$10b2o$5bo4b2o4bo16bo$3bobo9bobob2o12b
obo$4b2o10b2ob2o12b2o3$17b2ob2o$17bo3bo$18bobo$17b2ob2o$5b2o25b2o$4bob
o25bobo$6bo12bo12bo$18bobo$bo17bo17bo$b2o33b2o$obo33bobo2$9b2o17b2o$
10b2o15b2o$9bo19bo$22b2o$22bobo$22bo2$16b2o$15bobo$17bo!

I think that saves two gliders from the previous best.

[simsim314]

Here we go:

Yea!! That 7 gliders waste, was just so horrible.... Now we're at 5 (block + boat + block), which is great (and well done), my guess is 4 possible and 3 will be really fantastic.

One of the things might be done, is to use block instead boat, this might reduce one glider. Another approach would be to have 3 gliders with boat, or three gliders with block.

Finally there is some remote possibility two gliders and block would work somehow. This is remote possibility, but this is simple check (there are not many 2 gliders placements there), and would be really great. I'm working on it right now.

But this is really great! Nice to see how not being stuck with the recipe, and finding alternative approaches, might work for your benefit.

[chris_c]

Yea!! That 7 gliders waste, was just so horrible.... Now we're at 5 (block + boat + block), which is great (and well done), my guess is 4 possible and 3 will be really fantastic.

This is probably my closest near miss:

Code: Select all

x = 11, y = 9, rule = B3/S23
bo$2bo$3o4$6bo$2b2obobob2o$b2o3b2ob2o!

The obvious way to build it costs 6 gliders but conflicts with the left wing.

I had much less success with looking for ways to activate the block directly, but I did have vague hope with these:

Code: Select all

x = 60, y = 13, rule = B3/S23
3$b2o28bo19bo$17b2o$2bo14b2o12b2o19b2o$b2o2b2o10b2o2b2o8b2o2b2o15b2o2b
2o$b2o2b2o11bo2b2o9bo2b2o16bo2b2o$2bo15bo12b2o19b2o!

If any of the pre-centuries can be placed with 4 gliders it would give a reduction. Looks very difficult though.

[simsim314]

I had much less success with looking for ways to activate the block directly

There are many ways to activate the block, with very simple sparks - see here

[chris_c]

I had much less success with looking for ways to activate the block directly

There are many ways to activate the block, with very simple sparks - see here

I couldn't get any luck when searching for block + 1SL + 2G collisions.

Anyway, there is a new target to beat... luckily the block can be placed with only 1 glider:

Code: Select all

x = 27, y = 21, rule = B3/S23
26bo$24b2o$25b2o7$15bo$13bobo$14b2o3$16bo$16b2o$15bobo2$bo$b2o$obo!

[simsim314]

Anyway, there is a new target to beat... luckily the block can be placed with only 1 glider:

Wow great! This kind of luck is hard to beat... I think I'm happy with 28. The chances now to find better front, are probably close to find 5 gliders in the back. I run some random search looking for the back spark - and 6 is the best I've got. I also tried to find 4 for snake on snake - without any success.

Looks like everything is pretty tight right now. Let's see if someone can find something to improve, otherwise it's yet again a time for a gun

[dvgrn]

Looks like everything is pretty tight right now. Let's see if someone can find something to improve, otherwise it's yet again a time for a gun

It also looks as if the new synthesis will drop the repeat time back down to somewhere around 169 again. Is it even a few ticks lower now?

In any case there will be a new tangential optimization problem, to find the diagonally narrowest gun for the minimal period...!

[codeholic]

27 gliders and repeat time of 210

Code: Select all

x = 189, y = 193, rule = B3/S23
179bobo$179b2o$180bo$6bobo$7b2o5bo$7bo7bo2bobo160bobo$13b3o3b2o160b2o$
19bo162bo2$9bo170bo$7bobo168b2o$8b2o169b2o3$4bo179bo$5bo177bo$3b3o177b
3o4$155bo$155bobo$155b2o7$27bobo$28b2o$28bo8bo$38b2o$37b2o19$128bo$
126b2o$127b2o$59bo$60b2o$59b2o6bo3bo58bo$65bobo4b2o54b2o$66b2o3b2o56b
2o2$61bo$62bo63bobo$60b3o63b2o$127bo3$57bo73bo$55bobo73bobo$56b2o73b2o
3$103bo$102bo$102b3o7$80bo$81b2o$80b2o$89bobo$90b2o$90bo9$93bo$93b2o$
92bobo$82b2o12b3o$81bobo12bo$83bo13bo$103bo$67b2o33b2o$66bobo33bobo$
68bo5$93b2o$92bobo$94bo2$84b2o$85b2o$84bo7$57b2o71b2o$56bobo71bobo$58b
o71bo2$53bo81bo$53b2o79b2o$52bobo79bobo2$61b2o63b2o$62b2o61b2o$61bo65b
o$120b2o$120bobo$120bo2$68b2o$67bobo$69bo9$40b2o$41b2o$40bo108b2o$29b
3o117bobo$31bo117bo$30bo$155b2o$14b3o137b2o$16bo139bo$15bo5$40b3o$42bo
$41bo$32bo$32b2o$31bobo8$4b3o175b3o$6bo175bo$5bo177bo2$2o185b2o$b2o
183b2o$o187bo$9bo169bo$9b2o167b2o$8bobo167bobo2$172b3o$172bo$173bo2$
15b3o$17bo$16bo!

[chris_c]

27 gliders and repeat time of 210

Nice! That's a really cheeky 6 glider synthesis of double snake with appropriately placed tub.

Code: Select all

x = 21, y = 33, rule = B3/S23
5bobo$6b2o$6bo9$9bo$9b2o$8bobo$12b3o$12bo$13bo$19bo$18b2o$18bobo6$9b2o
$8bobo$10bo2$2o$b2o$o!

[Extrementhusiast]

p300 edgeshooter

I've gone back and forth there 10 times by now, I can't find anything relevant There are many small sparks, but nothing that clicks (for me at least).

It was meant to be the unit gun. However, since p210 is so convenient, here is an improved edgeshooter:

Code: Select all

x = 54, y = 90, rule = LifeHistory
11.2A$12.A$12.A.A$13.2A6$12.2A$12.2A4.2A$18.2A4$17.2A$13.2A2.2A$12.A.
A$12.A12.2A4.3D$11.2A11.A.A5.D$24.A7.3D$23.2A5$25.2A$24.A.A$24.A$23.
2A4$20.2A$20.2A3$33.A$20.3A9.A.A$20.3A8.2A.A5.A.2A$19.A3.A9.A6.2A.A$
18.A5.A$19.A3.A$20.3A2$2A$.A$.A.A5.2A$2.2A5.A.A31.2A$12.A28.A2.A$9.A
2.A27.A7.5A$12.A27.A6.A5.A$9.A.A28.A7.2A3.A$9.2A30.A2.A7.A$2.2A39.2A$
2.A2.A15.3A2$6.A$16.2A$4.2A11.2A16.3A$3.A12.A17.A3.A2$33.A5.A$2A3.2A
26.2A3.2A$2A3.2A$.5A3.A$2.A.A4.2A25.A$8.A.A24.A.A$2.3A30.A.A$19.A15.A
$18.A.A14.A$17.A3.A13.A2.A$17.A3.A14.2A$5.A11.A3.A$4.A.A10.A3.A$3.A3.
A9.A3.A$4.3A10.A3.A$2.2A3.2A9.A.A$19.A10$5.2A$5.2A!