Colorised Life
Colorised Life
So is it possible to create a reflector in Immigration which always inverts the color from red to blue and blue to red?
How about a reflector which turned one color into its anti-state in NiemecLife?
How about a reflector which turned one color into its anti-state in NiemecLife?
Re: Colorised Life
Probably, but I haven’t seen any. You’d just need to find a conduit which changes the color of something without any parts of the conduit. Sadly, a lot of conduits don’t work like that.PkmnQ wrote:So is it possible to create a reflector in Immigration which always inverts the color from red to blue and blue to red?
How about a reflector which turned one color into its anti-state in NiemecLife?
Code: Select all
x = 17, y = 23, rule = Immigration
6.2A3.2A$6.2A2.A.3A$10.A4.A$6.4A.2A2.A$6.A2.A.A.A.2A$9.A.A.A.A$10.2A.
A.A$14.A2$2A$.A7.2A$.A.A5.2A$2.2A7$12.2A$3.2B7.A$2.B.B8.3A$4.B10.A!
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x = 6, y = 13, rule = Immigration
.2A$2.A$.A$.2A6$B3.2A$2B2.2A$.2B$2B!
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x = 41, y = 36, rule = Immigration
2.B$B.B$.2B10$25.A$23.3A$22.A$22.2A$7.2A$8.A$8.A.2A$9.A2.A23.A$10.2A
24.A$25.2A9.3A$25.2A11.A4$34.A3.2A$33.A.A3.A$32.A.A3.A$28.2A.A.A3.A$
28.2A.A2.4A.A$32.A.A3.A.A$28.2A.2A2.A2.A.A$29.A.A2.2A3.A$17.2A10.A.A$
17.2A11.A!
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x = 17, y = 19, rule = Immigration
16.B$14.2B$15.2B10$4.2A$3.A2.A$3.A.A$.2A.A$A2.A$A.A$.A!
Also,
Code: Select all
x = 84, y = 87, rule = Immigration
16.B$14.2B$15.2B10$4.2A$3.A2.A$3.A.A$.2A.A$A2.A$A.A$.A3$17.A$16.A$16.
A4.A$16.5A38$78.A$76.2A$77.2A10$66.2A$65.A2.A$65.A.A$63.2A.A$62.A2.A$
62.A.A$63.A3$79.A$78.A$78.A4.A$78.5A!
EDIT:
A poly color SL synth
Code: Select all
x = 36, y = 19, rule = Immigration
23.A$22.A$18.B3.3A$.A14.2B$2.A14.2B$3A5$16.3A$16.A16.2B$17.A15.B.B$
33.B$2.2B$3.2B$2.B9.3B$12.B$13.B!
not active here but active on discord
Re: Colorised Life
For the HB, I found out that the bottom loaf dictates the glider color, and the top loaf dictates the reconstructed HB's loaves.
Re: Colorised Life
Actually, that’s only true when the bottom loaf is the color of the Glider; otherwise the top has the last say:PkmnQ wrote:For the HB, I found out that the bottom loaf dictates the glider color, and the top loaf dictates the reconstructed HB's loaves.
Code: Select all
x = 49, y = 20, rule = Immigration
48.A$16.B29.2A$14.2B31.2A$15.2B9$36.2B$4.2B29.B2.B$3.B2.B28.B.B$3.B.B
27.2A.B$.2A.B27.A2.A$A2.A28.A.A$A.A30.A$.A!
Code: Select all
x = 49, y = 55, rule = Immigration
48.A$16.B29.2A$14.2B31.2A$15.2B9$36.2B$4.2B29.B2.B$3.B2.B28.B.B$3.B.B
27.2A.B$.2A.B27.A2.A$A2.A28.A.A$A.A30.A$.A16$48.A$16.B29.2A$14.2B31.
2A$15.2B9$36.2A$4.2A29.A2.A$3.A2.A28.A.A$3.A.A27.2A.A$.2A.A27.A2.A$A
2.A28.A.A$A.A30.A$.A!
Blue = 1
Green = 0
First binary digit = color of top loaf
2nd Binary digit = color of bottom loaf
[ 10 10 ]
[ 00 00 ]
+
[ 1 0 ]
[ 1 0 ]
->
[ 11 11 ]
[ 00 00 ]
+
[ 1 0 ]
[ 0 0 ]
Let’s call these BAKEtrices
Technically, we need an additional 2 values for gliders.
Code: Select all
x = 116, y = 55, rule = Immigration
48.A66.A$16.B29.2A35.B29.2A$14.2B31.2A32.2B31.2B$15.2B65.2A9$36.2B65.
2B$4.2B29.B2.B32.2B29.B2.B$3.B2.B28.B.B32.B2.B28.B.B$3.B.B27.2A.B33.B
.B27.2A.B$.2A.B27.A2.A32.2A.B27.A2.A$A2.A28.A.A32.A2.A28.A.A$A.A30.A
33.A.A30.A$.A66.A16$48.A66.A$16.B29.2A35.B29.2A$14.2B31.2A32.2B31.2B$
15.2B65.2A9$36.2A65.2A$4.2A29.A2.A32.2A29.A2.A$3.A2.A28.A.A32.A2.A28.
A.A$3.A.A27.2A.A33.A.A27.2A.A$.2A.A27.A2.A32.2A.A27.A2.A$A2.A28.A.A
32.A2.A28.A.A$A.A30.A33.A.A30.A$.A66.A!
not active here but active on discord
Re: Colorised Life
I believe that in Immigration changing the colour of a cell in one generation can only change cells in later generations in the same direction. So a colour changing reflector is impossible.
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Re: Colorised Life
What about in QuadLife? Monotonicity doesn't hold there.
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x = 8, y = 5, rule = QuadLife
ABC2.ABD3$.D4.C$D.D2.C.C!
Re: Colorised Life
That's a good question. The other thing I'd like to see is an oscillator in QuadLife where for each of the colours there's a phase where that colour is completely missing.fluffykitty wrote:What about in QuadLife? Monotonicity doesn't hold there.Code: Select all
x = 8, y = 5, rule = QuadLife ABC2.ABD3$.D4.C$D.D2.C.C!