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Knyght (B2e3/S23-jq)

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Knyght (B2e3/S23-jq)

Postby drc » January 31st, 2017, 11:35 pm

This rule is named after its incredibly simple (2,1)c/9k knightship, shown here:
x = 5, y = 5, rule = B2e3/S23-jq
b2o$2obo$3b2o$bob2o$b3o!

It is natural, and it's not the only small spaceship, there are more, of speeds c/2o and 3c/8o:
x = 16, y = 51, rule = B2e3/S23-jq
4bo9b2o$5bo9bo$4bo9b2o$2o$bo$14b2o$15bo$14b2o2$12b4o$15bo$4bo9b2o$5bo$
4bo$14b2o$15bo$12b4o2$12b4o$15bo$14b2o3$14b2o$10bo4bo$10b6o2$10b6o$10b
o4bo$14b2o3$15bo$13b3o$13b3o$15bo3$15bo$13b3o$13b3o$15bo$13b2o3$13b2o$
15bo$13b3o$13b3o$15bo$13b2o!

There's a common weakly sparky p30:
x = 5, y = 5, rule = B2e3/S23-jq
2bo$o$2o$2b2o$4bo!

Guns couldn't be made with it no matter how hard I tried. However, there was another oscillator I found by hand, also p30:
x = 5, y = 7, rule = B2e3/S23-jq
o$bo$4bo$3bo$4bo$bo$o!

Doubling it up makes a neat p8 too:
x = 14, y = 7, rule = B2e3/S23-jq
o12bo$bo10bo$4bo4bo$3bo6bo$4bo4bo$bo10bo$o12bo!

I found a splitter reaction with the symmetric p30, phase-preserving too, and used it to make this: A p120n, four barreled gun. It can make p60n and p30n when doubled and quadrupled up:
x = 39, y = 39, rule = B2e3/S23-jq
9bo3bo$8bo5bo$11bo2$10bobo$11bo3$37bo$38bo$34bo$33bo2bo$34bo$38bo$37bo
2$11bo$10bobo$10bobo6$bo$o$4bo$2bo2bo$4bo$o$bo3$27bo$26bobo2$27bo$24bo
5bo$25bo3bo!

x = 39, y = 39, rule = B2e3/S23-jq
9bo3bo$8bo5bo$11bo2$10bobo$11bo3$37bo$38bo$34bo$33bo2bo$34bo$38bo$37bo
2$11bo$10bobo$10bobo2$26bobo$26bobo$27bo2$bo$o$4bo$2bo2bo$4bo$o$bo3$
27bo$26bobo2$27bo$24bo5bo$25bo3bo!

x = 39, y = 39, rule = B2e3/S23-jq
9bo3bo$8bo5bo$11bo2$10bobo$11bo3$37bo$38bo$20b2o12bo$22bo10bo2bo$20b2o
12bo$38bo$37bo2$11bo$10bobo$10bobo2$26bobo$26bobo$27bo2$bo$o$4bo12b2o$
2bo2bo10bo$4bo12b2o$o$bo3$27bo$26bobo2$27bo$24bo5bo$25bo3bo!

And a two glider synthesis for the big, sparky T glider leads to this:
x = 83, y = 42, rule = B2e3/S23-jq
24bo5bo$25bo3bo2$27bo25bo3bo$27bo24bo5bo$26b3o26bo2$54bobo$o54bo$bo$5b
o$3b3o75bo$5bo76bo$bo76bo$o76bo2bo$78bo$26b3o53bo$26bobo52bo2$55bo$54b
obo$54bobo3$38bo$37bo$33bo$33b3o9bo$33bo10bo$37bo10bo$38bo7bo2bo$48bo$
44bo$10b3o32bo$11bo$11bo$71bo$9bo3bo56bobo$8bo5bo$71bo$68bo5bo$69bo3bo
!

I'm sure more guns could be discovered, via glider synthesis, and new oscillators.

A reaction to make the big bulky asymmetric glider:
x = 5, y = 5, rule = B2e3/S23-jq
2o$bo$2o$4bo$3bo!


There's still the fact that we don't know how to eat the photon, desirable would be a p1 eater, although p2 would be fine, too.

Puffers are pretty decently plentiful in this rule. Here's a T-rake:
x = 3, y = 12, rule = B2e3/S23-jq
bo$2bo$bo7$bo$2o$bo!

And an omgwtfbbq puffer:
x = 3, y = 13, rule = B2e3/S23-jq
o$bo$o8$2bo$b2o$2bo!

Most puffers made from 'extending' photons don't work, S3-q is to blame, however, there's at least one that manages to survive long enough to create a p52 puffer:
x = 4, y = 7, rule = B2e3/S23-jq
2b2o$3bo$4o2$b3o$o2bo$2b2o!

There's also a p46 puffer, although if you go this far pretty much anything could be made a puffer, kind of like the line puffers from CGoL:
x = 5, y = 15, rule = B2e3/S23-jq
3b2o$4bo$3b2o2$b4o$4bo$5o$o$bob2o$o3bo$5o2$b4o$4bo$3b2o!

Bonus fun p2:
x = 7, y = 7, rule = B2e3/S23-jq
2bobo$obobobo$b2ob2o2$b2ob2o$obobobo$2bobo!
This post was brought to you by the letter D, for dishes that Andrew J. Wade won't do. (Also Daniel, which happens to be me.)
Current rule interest: B2ce3-ir4a5y/S2-c3-y
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Re: Knyght (B2e3/S23-jq)

Postby drc » February 1st, 2017, 3:01 pm

p240+30n oscillator:
x = 49, y = 49, rule = B2e3/S23-jq
13bo5bo$14bo3bo2$16bo16bobo$15bobo16bo2$32bo3bo$31bo5bo4$7bo$6bo$3bo
44bo$4bo42bo$3bo40bo$6bo38bo$7bo36bo$47bo$48bo10$o$bo$4bo36bo$3bo38bo$
4bo40bo$bo42bo$o26b2o16bo$29bo12bo$27b2o12bo4$11bo5bo$12bo3bo2$14bo16b
obo$13bobo16bo2$30bo3bo$29bo5bo!

p180+15(?)n oscillator, overclocking the block reaction:
x = 47, y = 51, rule = B2e3/S23-jq
14bo$13bobo$12bo3bo$12b2ob2o$12b2ob2o$13bobo13bobo$13b3o14bo2$11bo5bo
10bo3bo$12bo3bo10bo5bo4$45bo$39b3o4bo$o37bob4o$bo35bo5bo$4bo33bob4o$3b
o35b3o4bo$4bo40bo$bo$o11bo$11bobo$11bobo6$46bo$45bo$bo40bo$o4b3o35bo$
3b4obo33bo$3bo5bo35bo$3b4obo37bo$o4b3o$bo4$13bo5bo10bo3bo$14bo3bo10bo
5bo2$16bo14b3o$15bobo13bobo$30b2ob2o$13bo5bo10b2ob2o$14b5o11bo3bo$31bo
bo$32bo!

Glider shuttle:
x = 27, y = 24, rule = B2e3/S23-jq
9b3o$10bo$10bo2$8bo3bo$7bo5bo2$5bo$4bo21bo$o24bo$3o7b2o9bo$o11bo8b3o$
4bo5b2o9bo$5bo19bo$26bo4$13b3o$14bo$14bo2$12bo3bo$11bo5bo!

A p180/p90/p45 gun, by adding cycling gliders:
x = 30, y = 36, rule = B2e3/S23-jq
4bo5bo$5bo3bo2$7bo$6bobo3$25bo$26bo$29bo$28bo$29bo$26bo$25bo4$21bobo$
21bobo$22bo3$4bo$3bo$o$bo$o$3bo$4bo3$21bobo$22bo2$20bo3bo$19bo5bo!

SO DARN CLOSE:
x = 8, y = 22, rule = B2e3/S23-jq
o5bo$bo3bo2$3bo$2bobo13$4bo$3b3o2$bo5bo$2bo3bo!
This post was brought to you by the letter D, for dishes that Andrew J. Wade won't do. (Also Daniel, which happens to be me.)
Current rule interest: B2ce3-ir4a5y/S2-c3-y
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Re: Knyght (B2e3/S23-jq)

Postby Kiran » February 1st, 2017, 4:07 pm

Is there a rule table for this?
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Re: Knyght (B2e3/S23-jq)

Postby BlinkerSpawn » February 1st, 2017, 4:42 pm

Kiran wrote:Is there a rule table for this?

There's a script that should generate ruletables for any non-totalistic isotropic rule in this format but you don't need it if you get the latest version of Golly.
LifeWiki: Like Wikipedia but with more spaceships. [citation needed]

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Re: Knyght (B2e3/S23-jq)

Postby Kiran » February 1st, 2017, 9:38 pm

Updated Golly, found something potentially useful:
x = 147, y = 119, rule = B2e3/S23-jq
49bo2b2o$48bo3b2o18$108bo3b2o$109bo2b2o20$64bo5bo$65bo3bo2$67bo25bo3bo
$67bo24bo5bo$66b3o26bo2$94bobo$40bo54bo$41bo$45bo$43b3o75bo$45bo76bo$
41bo76bo$40bo76bo2bo$118bo$66b3o53bo$66bobo52bo2$95bo$94bobo$94bobo3$
78bo$2o75bo$2o71bo$73b3o9bo60bo$73bo10bo60bo$o76bo10bo$bo76bo7bo2bo$
88bo56b2o$84bo60b2o$50b3o32bo$51bo$51bo$111bo$49bo3bo56bobo$48bo5bo$
111bo$108bo5bo$109bo3bo23$93b2o2bo$93b2o3bo12$65b2o3bo$65b2o2bo!
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Re: Knyght (B2e3/S23-jq)

Postby BlinkerSpawn » February 1st, 2017, 10:37 pm

...is the eater the point of this post?
EDIT: Produces knightship:
x = 12, y = 6, rule = B2e3/S23-jq
9b3o3$2o$2bo$2o!

x = 11, y = 5, rule = B2e3/S23-jq
10bo$10bo$2o8bo$2bo$2o!
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Re: Knyght (B2e3/S23-jq)

Postby Hdjensofjfnen » February 3rd, 2017, 8:58 pm

Sorry if this has already been posted:

x = 5, y = 7, rule = B2e3/S23-jq
3bo$2b3o$2b3o3$2o$2o!
That that is, is. That that is not, is not. Is that it? It is.
A predecessor to my favorite oscillator of all time:
x = 7, y = 5, rule = B3/S2-i3-y4i
4b3o$6bo$o3b3o$2o$bo!
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Re: Knyght (B2e3/S23-jq)

Postby Kiran » February 6th, 2017, 9:23 am

BlinkerSpawn wrote:...is the eater the point of this post?

Yes.

Simple tethered rake:
x = 100, y = 87, rule = B2e3/S23-jq
62bo2b2o$61bo3b2o22$8bo$6bo3bo34bo5bo$10b2o34bo3bo$4bo5b2o$b3o4bobo37b
o$o47bo$b3o4bobo36b3o$4bo5b2o$10b2o$6bo3bo64bo$8bo65bo$58b2o10bo$59bo
10b3o$58b2o10bo$74bo$75bo10$37bo60bo$38bo60bo$42bo$40b3o$42bo55b2o$38b
o59b2o$37bo3$63b3o$64bo$64bo2$62bo3bo$61bo5bo23$46b2o3bo$46b2o2bo!
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Re: Knyght (B2e3/S23-jq)

Postby AbhpzTa » February 6th, 2017, 11:29 am

Slide gun:
x = 71, y = 55, rule = B2e3/S23-jq
9bo$8bobo2$9bo13b2o2bo$6bo5bo10b2o3bo$7bo3bo$4bo25bo$3bo25bo$33bo$31bo
2bo17bo$3b2o28bo17b3o$3b2o24bo$30bo13bo6bobo$44b2o5b3o$43b2o$44bo$42b
2o5bo5bo$50bo3bo4$69b2o$4bo64b2o$5bo$bo20b2o$o2bo18bo$bo20b2o$5bo$4bo$
23bo3bo$22bo5bo$25bo2$24bobo$25bo3$64bo$63bo$59bo$3b2o54b3o$3b2o54bo$
63bo$64bo$3bo$4bo$7bo3bo$6bo5bo32bo5bo$46bo3bo$8b3o$9bo38bo$48bo$7b5o
35bobo$6b7o35bo$8b3o36b3o!


EDIT:
3 more rakes:
x = 7, y = 73, rule = B2e3/S23-jq
4bobo$3bo2bo$4bobo8$bo$2o$bo18$3bobo$2bo2bo$3bobo10$o$bo$o16$bobo$o2bo
$bobo8$3bo$2b2o$3bo!

p1413 dirty knightpuffer:
x = 182, y = 134, rule = B2e3/S23-jq
115bo$115bo$111b3o2bo$112b2obo50b3o$115b2o47b3o$116bo46bo4bo$168bo$
164bo2bo19$126bo$128bo$123bo4bo$123bobo$128bo$110bob3o11bo2bo$109bobob
2o11bo2bo$109bobobo13b2o22bo$112bo38bo19b2o4b5o$113b2o32b3o2bo20bo2bob
obo$148b2obo19b2o3bo3bo$151b2o25bobo$152bo28bo$178bob2o64$39b3o$37b3o$
36bo4bo$41bo$37bo2bo13$17bo$19bo$14bo4bo$14bobo16b3o$19bo11b3ob2o$bob
3o11bo2bo10bobo$obob2o11bo2bo14b2o$obobo13b2o14b3o$3bo32bo18bo$4b2o29b
2o18bo$51b3o2bo$52b2obo$55b2o$56bo!
Iteration of sigma(n)+tau(n)-n [sigma(n)+tau(n)-n : OEIS A163163] (e.g. 16,20,28,34,24,44,46,30,50,49,11,3,3, ...) :
965808 is period 336 (max = 207085118608).
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Re: Knyght (B2e3/S23-jq)

Postby drc » August 14th, 2017, 8:30 pm

Bumping this thread because I think this rule will be easy to do things with. Also I just got my computer back and I've been itching to search.

bullet+2 blocks=2 bullets:
x = 14, y = 10, rule = B2e3/S23-jq
2o$bo$2o2$10b2o$10b2o3$12b2o$12b2o!

The second block can be moved down 9n cells:
x = 14, y = 19, rule = B2e3/S23-jq
2o$bo$2o2$10b2o$10b2o12$12b2o$12b2o!

Interesting T slowdown:
x = 23, y = 14, rule = B2e3/S23-jq
obo17bobo$bo19bo11$3b2o$3b2o!

T+2 blocks=(one time-)reflected T:
x = 14, y = 7, rule = B2e3/S23-jq
12b2o$12b2o$2o$3o$2o$12b2o$12b2o!

I found another one of those bullet-based spaceships. I am referring to these are bullet trains (I think that's a bit clever). This one's p12:
x = 10, y = 15, rule = B2e3/S23-jq
8b2o$9bo$8b2o$b2o3bo$3bo3b3o$o8bo$o2b7o2$o2b7o$o8bo$3bo3b3o$b2o3bo$8b
2o$9bo$8b2o!

An example of how messy this rule can be:
x = 47, y = 19, rule = B2e3/S23-jq
2b2o$o2bo$b3o2$4o$3bo$2b2o6$45b2o$43bo2bo$44b3o2$43b4o$46bo$45b2o!

No p1 eaters, unfortunately... I tried common constellations of blocks but no luck. There aren't many still lifes in this rule.
This post was brought to you by the letter D, for dishes that Andrew J. Wade won't do. (Also Daniel, which happens to be me.)
Current rule interest: B2ce3-ir4a5y/S2-c3-y
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Re: Knyght (B2e3/S23-jq)

Postby danny » July 4th, 2019, 12:18 am

Nearly 2 years later, I finally found an eater. Here it is in all its overly big glory:
x = 16, y = 17, rule = B2e3/S23-jq
8b2o$8bo$10bob2o$9b2ob2o2$9b2ob4o$9b2obo2bo$2o$bo$2o$9b2obo2bo$9b2ob4o
2$9b2ob2o$10bob2o$8bo$8b2o!


EDIT: 9c/24 eater and related component:
x = 42, y = 34, rule = B2e3/S23-jq
23bo$21b2o$20b2o4bo$20b2o5bo7b2o$20b2o4bo8bo$21b2o9b2obobo$23bo8bobob
2o$34bo$34b2ob3obo$38bob2o$34b3o$32bo2bo$32b2o3bo$36b2o7$o7bo14bo$22bo
$2bo3bo15bo3bo$27bo7b2o$4bo21bo8bo$20bo11b2obobo$2bo3bo13bobo9bobob2o$
34bo$o7bo25b2ob3obo$38bob2o$34b3o$32bo2bo$32b2o3bo$36b2o!
she/they // Please stop using my full name. Refer to me as dani.

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Re: Knyght (B2e3/S23-jq)

Postby Hdjensofjfnen » July 4th, 2019, 1:18 am

Wow. I posted the 6c/16o in another thread under B2e3/S23-j and dani posts it in Knyght to enlighten me less than 12 hours later.
EDIT: Wait, I posted it in Feb 2017. Double fail.
That that is, is. That that is not, is not. Is that it? It is.
A predecessor to my favorite oscillator of all time:
x = 7, y = 5, rule = B3/S2-i3-y4i
4b3o$6bo$o3b3o$2o$bo!
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Re: Knyght (B2e3/S23-jq)

Postby CoolCreeper39 » August 10th, 2019, 9:58 pm

Methuselahs in Knyght (Non record-breakers are not counted):

1-cell bounding box: 1G
x = 1, y = 1, rule = B2e3/S23-jq
o!


4-cell bounding box: 14G
x = 1, y = 4, rule = B2e3/S23-jq
o$o$o$o!


8-cell bounding box: 24G
x = 2, y = 4, rule = B2e3/S23-jq
bo$bo$2o$2o!


9-cell bounding box: 56G
x = 3, y = 3, rule = B2e3/S23-jq
2bo$2o$3o!


10-cell bounding box: 341G
x = 2, y = 5, rule = B2e3/S23-jq
bo$2o$bo$o$2o!


11-cell bounding boxes failed to produce any more record-breakers.
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